Recent content by jberg074

Ah, I understand now. I wasn't exactly sure what the question was asking for at first; thank you very much for the help!

\{(a,b,2b-a/2,4b+a/2)~\vert~a,b\in \mathbb{R}\} I used other questions to eliminate variables and to try and get a in terms of the other. However, in the text above, shouldn't "a" be replaced by "a/2"?

Is the answer as simple as this? a=6b-c b=b c=2b-a/2 d=4b+a/2

Homework Statement Let U be the span of [ 0 ] [ 2 ] [ 1 ] and [ 0 ] [ 2 ] [ -1] [ 4 ] [ 1 ] Give conditions on a, b, c and d so that [a b c d] (transposed) is in U (as in, give restrictions that are equations of only a, b, c and d. Homework Equations The Attempt at...

Allright, thank you so much for your help!

a) To get 1, I'm guessing we'd have to divide by (2+k)? Since (2+k)/(2+k)=1. However, this operation would have to carry through the whole row, right? b) I'm not sure at all. They can't each equal zero, because that would yield k=-2 and k=1, which would turn it into an inconsistent system. c)...

Using the following steps: R3=R3+R1, and R3=R3-R2, I get: [ 1 0 3 0 ] [ 0 1 1 1 ] [ 0 0 (2+k) (k-1)] Unless we have to get it in this form? [ 1 0 3 0 [ 0 1 3+k k [ 0 0 -(2+k) 1-k

Hi, the following linear algebra question is causing trouble for me: For which values of k does the following system of equations have a) a unique solution, b) infinite solutions, and c) no solutions? [ 1 0 3 | 0 ] [ 0 1 1 | 1 ] [ -1 1 k | k ] I know that having a unique...