Recent content by jbgibson

That's it! I worked out the problem using I about the suspension point and it's correct. Thank you for the insight.

Homework Statement A physical pendulum is constructed using a 4.4 kg object having a moment of inertia of 33.9 kg-m2 about its center of mass. The rotation (suspension) point is 276.69 cm from the center of mass. What is the period of this physical pendulum? Homework Equations T =...

Yes, I'm trying to solve the energy ratio. I did take into account that vf has units of cm/s. Under normal circumstances, hf = 0, and vf>vi. I made the assumption, based on the values given, that hi = 0, and that an upward force is being applied.

What is the energy ratio (Ef/Ei) of a system on Earth that has a final velocity of 3901.5 cm/s, initial velocity of 249.9 m/s, and a height of 0.006 km. E = K + U = 1/2mv^2 + mgh Ef = 1/2mvf^2 + mghf Ei = 1/2mvi^2 + mghi It appears that the object is being forced upwards since...

If I know the acceleration of gravity (9.81m/s^2), and I'm given an initial velocity in the positive x direction, how would I go about figuring how far will an object fall in a given time? I think this a 2-dimension projectile, but I don't see how to solve. If y=yo+vot-1/2gt^2, then...

Any help is greatly appreciated.

If a=-g=-1.6m/s^2 on the moon, is the solution to problem #1: y=-1/2gt^2=-96.8cm? I submitted this as my answer, but it is incorrect. I don't know anymore; maybe I should just give up.

I'm not able to visualize the concept right now. I realize the problems are dealing with 2-dimensional application, but I'm puzzled. I tried applied the formulas: y=yo+vot+1/2gt^2 y=1/2gt^2 y=(vo sin)t-1/2gt^2 Let's see...my initial velocity in the y-position is 0 and I don't have any...

I'm having difficulty with these two problems: 1. A mass is moving towards a massive crater (along the +x direction) on the Moon with an initial velocity of 636.8 cm/s. How far will the object fall in the first 1.1 seconds. 2. An object initially displaced 56.8 m (along the horizontal x...

Thanks for the quick response Doc! I think I got it. Here it is: (T*sin theta)H - mg(H/2) and solve for T

I think I got it! If I know the Tx = mg(H/V) and Ty = mg, I should be able to use pythagorean theorem right?

Is the y component of tension = mg? I seem to still be lost on this one. Now that I have solved for theta, I get 70.53 degrees, where do I go from here? Thanks for the help!

Man, I feel dumb! Now that I know the length, would I use the formula: T = mg(H/V)?

I have the length of the string and the mass of the stick; that's it.

I still don't have a clue where to go with this. I was in error, there is no sqrt., but the solution I'm getting is incorrect. The answer to this problem is 0.0072-N*m. How is that? What am I doing wrong?