What Determines the Period of a Physical Pendulum?

AI Thread Summary
The discussion centers on calculating the period of a physical pendulum using the formula T = 2π√(I/mgh). The user provided the mass (4.4 kg), moment of inertia (33.9 kg-m²), and the distance from the center of mass to the suspension point (2.7669 m). Initial attempts yielded a period of 3.35 seconds, but clarification was needed regarding the use of inertia about the suspension point rather than the center of mass. Ultimately, the user confirmed that recalculating with the correct inertia led to the correct solution.
jbgibson
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Homework Statement



A physical pendulum is constructed using a 4.4 kg object having a moment of inertia of 33.9 kg-m2 about its center of mass. The rotation (suspension) point is 276.69 cm from the center of mass. What is the period of this physical pendulum?


Homework Equations



T = 2pi sq rt (I/mgh)

The Attempt at a Solution



Every attempt at this problem yields T = 3.35s. I did a little research to make sure I was using the correct equation, but I didn't find anything to contradict what I'm using. Inertia is kg-m^2; m=4.4kg, g=9.81m/s^2, and h=2.7669m. Any help is appreciated.
 
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Note that I must be about the suspension point, not the center of mass.
 
Doc Al said:
Note that I must be about the suspension point, not the center of mass.

That's it! I worked out the problem using I about the suspension point and it's correct. Thank you for the insight.
 

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