Recent content by JCB

Your looking for the KE just before the ball hits the floor. In order to do that, you need to first find it's velocity just before it hits the floor. So you do PEi + KEi = PEf + KEf. KEi goes to 0 since it's starting from rest, and PEf goes to 0 since y=0 just before it hits the floor. So...

PE = mgy but I don't need any help on this. I realized what I did wrong: nothing! I got v^2 to be 39.2, and forgot to solve for just v. That would explain a lot.

Homework Statement A 7kg bowling ball falls from a 2m shelf. Just before hitting the floor, what will its kinetic energy be? (air resistance is negligible)Homework Equations PEi + KEi = PEf + KEf KE = 1/2mv^2The Attempt at a Solution m = 7kg Δy = 2m g = 9.8m/s^2 Vi = 0 m/s I solved for the...