Recent content by jchojnac

for x = 0 (at center of loop) B = (μ0)*(I)/(2*R) don't know how to get b, c, or d yet though.

how do you solve for T?

never mind, i got it

Does anyone know how to do the very last part on question 1?... There are 100 atoms in this object. What is the heat capacity on a per-atom basis? (Note that at high temperatures the heat capacity on a per-atom basis approaches the classical limit of 3k = 4.210-23 J/K/atom.) Heat capacity per...

1.054e-34*sqrt((4*12)/(.012/6.02e23))...i followed this with my numbers

i got the first question right with that equation, but I'm talking about the table and calculating the energy.

whenever I calculate the energy, I get an error on my calculator b/c it can't do 4.91e26 factorial. How did you input that as an answer?

E: 4e-21, 6e-21, 8e-21, 1e-20, 1.2e-20, 1.4e-20, 1.6e-20 # ways: 6, 20, 37, 60, 90, 122, 148 This might be easier to read

Homework Statement Object A and object B are two identical microscopic objects. The table below shows the number of ways to arrange energy in one of these objects, as a function of the amount of energy in the object. E (joules) 4e-21 6e-21 8e-21 1e-20 1.2e-20 1.4e-20 1.6e-20 #...

I added L of the wheel and L of clay. I also subtracted them and they were both incorrect. Is it the calculations?

so the L for the wheel is I*omega where I = (8*.5)(.9)^2 and omega is just the .35rad/sec. Then you add that to the L of the clay which is R*p where R=1.8*(sqrt(2)/2)) and p = (.25*8). If so, i got it wrong.

Homework Statement A device consists of eight balls each of mass 0.5 kg attached to the ends of low-mass spokes of length 1.8 m, so the radius of rotation of the balls is 0.9 m. The device is mounted in the vertical plane. The axle is held up by supports that are not shown, and the wheel is...

for part d.) isn't it Lf-Li where Li is part a.) and Lf is I * omega with the given time?

I still don't understand how you get the vector r.

I'm still confused how you got b. You find K for each by K = 1/2mv^2. And you find v by p/m. But how do you find p from p^2/(2*m(proton)) + p^2/(2*m(deuteron)) = Uelectric? If Uelectric = 1/(4*pi*epsilon)*Q*q/r is from parts c & d then how are you supposed to get b? I'm really confused.