Recent content by jcvince17

now i solved part D and Part E. thanks

i found a new equation in the book. K = 13.6 ev / n^2 U = -27.2 eV / n^2 E = K + U i knew E = 13.6. I finally got them all to work out without having to deal with the error's in the exponents.

well i am trying to work out the units only to make sure i have the equation right. but i am not ending with eV E0 = C^2/N x m m = kg e = C h = J x s (or N x m x s) n = unitless i get: (1/m)(kg x C^2 / s) i can't convert or cancell anything else out. this problem is driving me insane

i tried doing the exponents separately: for the me^4 part of equation (1.67 x 10^-27) x (1.602 x 10^-19)^4 = [ 1.67 x 1.602^4 ] x 10^[-27- (19x4] = 10.99 x 10^-103 that looks very wrong. and when i try to divide/multiply it by something i get an error in the calc's. now what am i...

what is the correct mass of Hydrogen. I am using 1.66x10^-27. But when i do so and multiply it by e^4 i get 0. which makes everything 0 and this is incorrect.

I fixed my equations. now using the first equation to find K. I used the following values: E0 = 8.854x10-12 m = 1.66*10-27 (i think that's right for Hydrogen) e = 1.602x10-19 h = 6.626x10-34 n = 1 Kn = (1/E02)(me4/8n2h2) plug in the values and i get K = 1.28x1022 x 12.17 K =...

Homework Statement Consider a Hydrogen atom in the ground state Find: A- The Kinetic Energy, in eV B - The Potential Energy, in eV C - The Total Energy, in eV D - minimum energy required to remove the electron completely from the atom, in eV E - What wavelength does a photon with the...

This is due at 11pm tonight, if anyone can please help me. I don't know where I am going wrong here. Thanks.

tried it again lens 1: 1/f = 1/s' + 1/s 1/10 = 1/s' + 1/30 s' = 7.5 = @ x = -12.5 lens 2: 1/f = 1/s' + 1/s 1/8 = 1/s' + 1/32.5 s' = 10.6 = final image is at x = + 30.6 ?

well, I have gotten several wrong answers and have only two chances left. edit - still working on it i found something about solving for a resultant focal point. F = 1 / f1 + 1 / f2 - d / f1f2 F = (1/10 + 1/8) - (40/10*8) F = -.275 if i then take this into my original equation...

no problem...i am the same way sometimes. sometimes you just need a clear head to straighten it out.

i do it i get: 1sin90 = 1.33sin(theta 2) 1 = 1.33sin(theta 2) 1/1.33 = sin(theta 2) .7518796992 = sin(theta 2) sin-1(.7518796992) = 48.75 degrees

Homework Statement A compound lens system consists of two converging lenses, one at x= -20cm with focal length f1 = +10cm, and the other at x= +20cm with focal length f2 = +8cm . An object 1 centimeter tall is placed at x = -50cm. What is the location of the final image produced by the...

doing so i get: 1/-15 = 1/s' + 1/3.4 s' (head) = -2.77 1/-15 = 1/s' + 1/5 s' (feet) = -3.75 so i subtract these two numbers and have an answer of 0.98 m Thank You!

Homework Statement A guy named Joe, who is 1.6 meters tall, enters a room in which someone has placed a large convex mirror with radius of curvature equal to 30 meters. The mirror has been cut in half, so that the axis of the mirror is at ground level. As Joe enters the room, he is 5...