For the common isotope of nitrogen, 14N, calculate the mass defect.
\DeltaM = Zmp + Nmn - M
The Attempt at a Solution
\DeltaM = .108516177
Masteringphysics says this is wrong. says i may...
well i am trying to work out the units only to make sure i have the equation right. but i am not ending with eV
E0 = C^2/N x m
m = kg
e = C
h = J x s (or N x m x s)
n = unitless
(1/m)(kg x C^2 / s)
i cant convert or cancell anything else out. this problem is driving me insane
i tried doing the exponents seperately:
for the me^4 part of equation
(1.67 x 10^-27) x (1.602 x 10^-19)^4
= [ 1.67 x 1.602^4 ] x 10^[-27- (19x4]
= 10.99 x 10^-103
that looks very wrong. and when i try to divide/multiply it by something i get an error in the calc's.
now what am i...
I fixed my equations.
now using the first equation to find K. I used the following values:
E0 = 8.854x10-12
m = 1.66*10-27 (i think thats right for Hydrogen)
e = 1.602x10-19
h = 6.626x10-34
n = 1
Kn = (1/E02)(me4/8n2h2)
plug in the values and i get K = 1.28x1022 x 12.17
Consider a Hydrogen atom in the ground state
A- The Kinetic Energy, in eV
B - The Potential Energy, in eV
C - The Total Energy, in eV
D - minimum energy required to remove the electron completely from the atom, in eV
E - What wavelength does a photon with the...
well, I have gotten several wrong answers and have only two chances left.
edit - still working on it
i found something about solving for a resultant focal point.
F = 1 / f1 + 1 / f2 - d / f1f2
F = (1/10 + 1/8) - (40/10*8)
F = -.275
if i then take this into my original equation...
A compound lens system consists of two converging lenses, one at x= -20cm with focal length f1 = +10cm, and the other at x= +20cm with focal length f2 = +8cm . An object 1 centimeter tall is placed at x = -50cm.
What is the location of the final image produced by the...