Recent content by Jd303

Thanks guys I think I got it: Let u = z^3 find Taylor series for f(u) sub back in z^3 integrate term by term to find F(z)

Let F(z) be the anti-derivative of the function f(z) = cos(z^3) with F(0) = 0. Express F(z) as a power series around z=0, giving both the first 3 non-zero terms and the general (nth) term. Hey guys really struggling with this integration and how to then express this as a power series. Any...

Can you time delay in MIPS?

Hi all, I've only just started MIPS and have been stuck on this introductory lab for a while now. I have 8 LEDs each lit by there corresponding bit being a 1. Hence 0010 0101 at the input would light up LEDS 1, 3 and 6. I need to make LEDs 1-5 light up one at a time and extinguish the...

Not to worry, figured it out you can obtain phase and magnitude directly from H(z), also normalised frequency is just omega divided by the sampling rate

Hey all, I am having trouble with this problem: A sampled sinusoidal signal having a normalized frequency of 0.30π is sent through an FIR filter. The filter impulse response is, h[n] = 1/3δ[n] + 1/3δ[n-1] + 1/3δ[n-2] From this I must find out by what factor the input signal is...

Hey everyone, the question I am faced with is this: Which of the following expressions involving δ[n] is incorrect? where "m" is a non zero integer and u[n] is the unit step function. A. u[n-m] = δ[n] + u[n-m+1] B. x[n]δ[n-m] = x[n-m] C. δ[n] = u[n] - u[n-1] D. δ[n]δ[n-m] = 0...

The input signal to an analog to digital converter is x(t) = 5.4 cos (134.5πt + 0.1π). The output from the converter is y(n) = 5.4 cos (0.47πn - 0.1π). Compute the sampling frequency (samples per second) of the analog to digital converter. Hint: the continuous-time input signal is...

For more context, this is multiple choice with the following values: A. 9.80cos(1330.56πt + 0.06π) + 1.90cos(2513.28πt - 0.41π) B. 9.80cos(1064.45πt - 0.06π) + 1.90cos(5026.56πt - 0.41π) C. 9.80cos(2661.12πt - 0.06π) - 1.90cos(1759.30πt + 0.41π) D. 9.80cos(1330.56πt - 0.06π) + 1.90cos(2513.28πt...

The discrete-time spectrum of a sampled continuous-time signal x(t) is shown in the figure above, where (A = 9.8exp(-j0.06π), B = 0.51π, C = -0.27π, and D = 1.9exp(-j0.41π) ). If the sampling frequency is 4928, which of the following continous-time signals is a possible solution for x(t)...

Just had a breakthrough, needed to get away from the problem and then look at it again. Just in case anyone wants to correct me: -2*pi*fo/fs = 0.8*pi -Therefore fo = 231.36 -Therfore possible frequencies are fo +-fs*k where k is an integer

Let, x(n) = 3.9 cos(0.80πn + 0.2π) be the discrete-time signal obtained by sampling a continuous-time signal x(t) at a sampling rate of 578.4 samples/sec. Find possible expressions for x(t). Hey all, I am quiet unfamiliar with this type of question, and haven't been able to put anything...

Thanks for the expression, I have since found that i had a calculation error, but fixing this up leaves me with a result of 0. I have tried this both using exponentials and trigonometric identities both yielding a final answer of 0. Can anyone point me in the right direction or plot out some...

P = (V^2)/R Hence power percentage would be 0.8488^2.! Hopefully I have finally gotten that one right! Thanks for your persistence with me

Yes I have actually looked at that page, but it just isn't clicking, here is my understanding. -The zero harmonic is the DC component and hence 0.5 -Even harmonics have a value of 0 -Odd harmonics have a value of 2/(pi*n) -Total amplitude is 1 -So percentage power should be ((2/pi) + 2/(3*pi))/1...