Power contained in a periodic signal (complex exponentials)

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The discussion focuses on computing the power of the periodic signal x(t) = 10.0[cos(160.7πt)]^4, with the user encountering issues leading to a constant value for ak across all k. They initially applied the inverse Euler formula and performed integration, but faced challenges distinguishing between odd and even k values. An expansion for cos4(x) was suggested, which was acknowledged as potentially useful. Despite correcting a calculation error, the user continues to arrive at a power result of 0 using both exponential and trigonometric methods. Guidance is requested for the correct procedure to compute the power effectively.
Jd303
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Compute the power contained in the periodic signal x(t) = 10.0[cos(160.7πt)]^4

The problem I have is I end up with a constant value for ak for all values of k
-I start by using inverse Euler formula
-Do the appropriate integration
-Then consider k for odd and even values

My working is attached, if anyone is able to show me the correct procedure, or is able to shed some light for me to understand the topic better it would be much appreciated.
 

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Power = energy per integer number of periods/time of that number of periods
= ∫x(t)2dt over n periods T/nT.

An expansion I found that might be useful is
cos4(x) = (1/8)[3 + 4cos(2x) + cos(4x)].
 
Thanks for the expression, I have since found that i had a calculation error, but fixing this up leaves me with a result of 0. I have tried this both using exponentials and trigonometric identities both yielding a final answer of 0.

Can anyone point me in the right direction or plot out some steps?
 
Jd303 said:
Thanks for the expression, I have since found that i had a calculation error, but fixing this up leaves me with a result of 0. I have tried this both using exponentials and trigonometric identities both yielding a final answer of 0.

Can anyone point me in the right direction or plot out some steps?

Perform the integration!
 
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