Recent content by Jerremy_S

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    Engineering Designing 3-Stage Async Counter & Logic Circuit in PSpice

    Thanks! Just realized that! 2^3=8 states (0 to 7). Not sure how to decode 3 inputs into 4 outputs designing a logic circuit. Any hints?
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    Engineering Designing 3-Stage Async Counter & Logic Circuit in PSpice

    Does it mean that using 10 different output states (0 to 9) as an input to the logic circuit would be a good approach?
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    Engineering Designing 3-Stage Async Counter & Logic Circuit in PSpice

    Homework Statement The block diagram of FIGURE 3 shows a three-stage asynchrononous counter that is used to count a series of randomly occurring input pulses. The ‘Q’ outputs of the counter are used to drive a logic circuit that gives the output shown in TABLE 1. (a) Design the counter using...
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    How to Derive the Laplace Transfer Function for a Parallel RC Circuit?

    Hi, Would you be able to help please. The question is 1) Draw the Laplace form of the input portion of the circuit. The diagram shows a Norton current source (ip) in parallel witch a capacitor (Cp) ( attachment in post #1). Is it the same as a Thevenin equivalent circuit with Cp in series...
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    Triac - Power dissipated in light bulb

    Hi All, Having given a= π/3 Can you explain why b= 5π/3 ? And Also, where this integral formula comes from? What is it called? I am going back and forth through my textbooks and I cannot find anything. A push in the right direction would be appreciated:) Thanks
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    High voltage transmission line with ABCD complex equations

    Hi Guys, I am struggling with this question as well. Could you explain, how we get from this ABCD matrix formed from a T - network to the Z=A-1/C and Y=1/C ?? How the above equations are obtained? Please help
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    Leq = (L1*L2-M^2)/(L1*L2-M^2)Hope this helps

    Thanks for your reply:) So it looks like Lt should be found first and then used as L in the resonance equation giving 0,75L = 25,33 x 10^-6Hr = 33,77x10^-6 ? I hope that amount of L's is about right this time... Cheers
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    Leq = (L1*L2-M^2)/(L1*L2-M^2)Hope this helps

    Hi All, I am a bit confused about part d): I calculated L using: L = 25,33 x 10^-6Hr Next, knowing that M=kL and k=0,5 I Calculated Lt: Lt = (L1L2 - M^2)/(L1+L2-M2) = (L^2-M^2)/(2L-2M) = (L^2 - 0,25L^2)/L = 0,75L^2/L = 0,75L Then: Lt = 0,75 * (25,33 x 10^-6Hr) = 18,9975x 10^-6 I am...
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