Um I am not sure if I get what you are trying to say but I have given it some thought and come up with the following!
if X1 =1then that means bead 1 = pink and bead 2 = blue , or bead 1 = blue and bead 2 = pink
so P (X1 =1 ) = (2/3)(1/3)+ (1/3)(2/3) = 4/9
and P (x1= 0) = 5/9
Do I just...
1. A necklace consists of 5 beads on a string. The beads for making the necklace are drawn at random from a box containing a very large number of beads. 2/3 of the beads are pink and 1/3 are blue. find the mean and variance of the number of unlike pairs of adjacent beads in the necklace.
I am...
1. Suppose X is a random variable with probability function
f(x) = 0.49x(0.3)^ (x-1). Find E(x).
2. E(X) = sum of all x of x*f(x)
3. so I know that E(X) = sum of all x of x*f(x)
so E(x)= 0.49* sum of all x of x^2(0.3)^(x-1)
But I'm not sure how do i evaluate the sum?
Can...
Hi everyone!
I was wondering if someone could help me with the following question with partial derivatives.
A function f: R^2 -> R is defined by f(x,y) = g(x-2y), where g: R-> R.
If g'(1)= 3, calculate f subscript x (3,1) and f subscript y of (3,1).
thanks!