Recent content by jessicak

That would be the problem, thank you.

The attached thumbnail would be my interpretation of the problem, where the masses are "anchored" by repulsion, giving the distance between them to be 28cm. Therefore, by saying anchored, we know that the net force is 0. Am I approaching this the wrong way?

Homework Statement Suppose that two balls of mass 1.5x10-4kg each carry equal charges and are suspended by identical threads of length 11cm anchored 28cm apart. If each thread makes an angle of 20 degrees with the vertical, what is the charge on each ball? Homework Equations F=kq2/r2The...

I feel a little silly now, thanks!

I'm getting 8kQq/L2cos45 I have online hw, so when I submit it it's not correct, but I'm not seeing where I'm going wrong

Homework Statement Four point charges of +/-Q are arranged on the corners of a square of side L. What is the net electric force that these charges exert on a point charge q placed on the center of the square (formula in terms of Q, q, L and Coulumb constant k)?Homework Equations F=kQq/r^2The...

1. Homework Statement A projectile is launched with speed v0 at an angle with respect to the horizontal. At the peak of its motion, it explodes into two pieces of equal mass, which continue to move in the original plane of motion. One piece strikes the ground a horizontal distance D farther...

Yes, they were. I was a little surprised by the values, though.

ok, so i have all the questions of part a answered 130m asteroid: -0.00354m/s 420m asteroid: 0.000588m/s However, when I try to use the formula for the final velocity (vf= (m1v1 +m2v2)/(m1 +m2) I get -1.88x10-6 which my online homework rejects. Thoughts?

Unfortunately, my online homework does not accept that answer as correct. However, I am confident that time needs to be present somewhere, as the question distinctly asks for it.

They are at rest initially. The problem asks to find the velocity of the asteroids right before their collision. They are attracted to each other, and therefore have some velocity before they hit.

The general kinematic equation for height of a projectile is h= v02sin2\theta/g How can I adjust this for the explosion? (I think time fits in there somehow)

Hmmm... I'm still very lost. If I take into consideration the time it takes for the first piece to reach the ground, how does that help me find the height of the second piece?

Homework Statement A projectile is launched with speed v0 at an angle \theta with respect to the horizontal. At the peak of its motion, it explodes into two pieces of equal mass, which continue to move in the original plane of motion. One piece strikes the ground a horizontal distance D...

1. Homework Statement Two asteroids of 1.0x107kg and 6.0x107kg respectively, are initially at rest in interstellar space separated by a large distance. Thier mutual gravitational attraction then causes then to fall toward each other on a straight line. Assume the asteroids are spheres of...