Ok... Since the distance from the point to the origin is d, then we can say that the distance from the point to the plane would be z-4
So in the equation, d = z-4
Thanks for all the help!
I'm still not understanding what I have to correct.
I guess I don't really understand what should be plugged in for d. From my understanding, d is going to have to be some type of function because it is changing as the surface changes to different points "G"?
For the distance formula between arbitrary point (x,y,z) on the surface to the plane z=4 would be;
D1= abs(ax+by+cz+d)/sqrt(a^2+b^2+c^2) where n=<a,b,c> is the normal vector to the plane z=4, which we can say is <0,0,1>.
So D1=abs(0x+0x+1z)/sqrt(0^2+0^2+1^2) = abs(z)
And the distance...
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Homework Statement
A given surface contains all points G such that the distance from G to the plane z=4 is double the distance from point G to the pt. (2, -3, 1). Find eqn for the surface.
Homework Equations
I thought the distance formula for a point to a plane would help, but I can tell...