Recent content by Jimmy5050

Any takers? I'm sure I have the answer right, just not sure of the "correct" last couple steps to get to that answer so that I can show work properly.

I meant it as d, not D1. I now realize its a constant, so solving through with that same logic should just give d= -4?

Ok... Since the distance from the point to the origin is d, then we can say that the distance from the point to the plane would be z-4 So in the equation, d = z-4 Thanks for all the help!

I'm still not understanding what I have to correct. I guess I don't really understand what should be plugged in for d. From my understanding, d is going to have to be some type of function because it is changing as the surface changes to different points "G"?

For the distance formula between arbitrary point (x,y,z) on the surface to the plane z=4 would be; D1= abs(ax+by+cz+d)/sqrt(a^2+b^2+c^2) where n=<a,b,c> is the normal vector to the plane z=4, which we can say is <0,0,1>. So D1=abs(0x+0x+1z)/sqrt(0^2+0^2+1^2) = abs(z) And the distance...

Parameterizing vector function for intersection of cylinder and plane Homework Statement Problem asks us to find the vector function of the curve which is created when the plane y= 5/2 intersects the ellptic cyl. (x^2)/4 + (z^2)/6 = 5 Homework Equations The Attempt at a...

Homework Statement A given surface contains all points G such that the distance from G to the plane z=4 is double the distance from point G to the pt. (2, -3, 1). Find eqn for the surface. Homework Equations I thought the distance formula for a point to a plane would help, but I can tell...