Recent content by jimvoit

If angles are measured positive counter-clockwise from the positive x-axis (as standard) then your value for B is incorrect.

Instead of using the quotient rule, you might find it easier to evaluate 3 x^-2

You have been given that i and j are directed to the east and north. This follows the standard convention for a 2D Cartesian coordinate system in which i and j are directed along the positive x and y-axis respectively. In this system, a unit vector with a direction alpha, measured...

It is a good idea to make carefull use of parentheses so that there is no ambiguity as to the meaning of an expression. Consider that for positive constants k, and vectors v, k v is in the same direction of v.

This might also help you with these kind of problems: You have three vectors a, b, c: The wind velocity a=(a1,a2) The velocity of the airplane through the air b=(b1,b2) The velocity of the airplane along the ground c=(c1,c2) The...

You might be interested in the paper: Mathematical Notation: Past and Future (2000). Stephen Wolfram October 20, 2000.

Your also need to also estimate the distance from your eye to the pencil. Draw a picture...there are two similar triangles involved

Two vectors have a magnitude of 86.4 and an x coomponent of 62.3: In the first quadrant (62,3, 59.9) In the fourth quadrant (62.3, -59.9) Their polar coordinates are: In the first quadrant (86.4, 43.86 degrees) In the fourth quadrant (86.4, -43.86 degrees)

What would be the force on the mans feet if he and the elevator were in free fall? Zero ?

The cut and paste did'nt work too well, but if you let the small square be the symbol for angle, then my results are: afe=156; cde=140; ed=60; 2=afe/2; 1=90-2; 3=1; 4=90; 7=ed/2; bc=180-cde; 6=bc/2; 9=180-6-7; 10=180-9; 5=90-10; 8=90-5-6; 1,2, 3, 4, 5...

I should have said arc AFE. It's clear in the thumbnail sketch that its arc AFE, arc CDE and arc ED that they are talking about because they use the "hat" symbol above the letters. In any future posts I'll make sure I'm clear about whether its angles or arcs I'm talking about.

Correct above post to read "AFE is ..."

AFC is 156 degrees. The symmetry of the construction indicates that angle_2 is half that. (78 degrees). Since OAP is a right triangle, angle_1 is 90-Angle_2. (12 degrees)

angle 1 = 90 - angle 2 = 90 - (156/2) = 12 This may be incorrect, but if the drawing is to scale then angle 1 is not 66 degrees.

The computer algebra system Mathematica uses the term "Bracketing" in the following way: Four kinds of bracketing: (term) parenthesis for grouping f[x] square brackets for functions {a,b,c} curly braces for lists v[[i]] double brackets for indexing Notice that "bracket" is...