Recent content by jljarrett18

This is what I have come up with so far:This is what I have come up with so far: Given any pair of reflections there exists a rotation or translation that produces the same results. I started this task with reflections. I started with an example I created in GSP5. In this example I created a...

So now I can prove the dimensions of square are (√2)/4. With that information I then can fill in the rest of the shapes of the tangrams because I know one length of the square?

Would the answer to my question be as a shape is reflected, a rotation can be made to rotate the shape and then a translation can be used to pick up the shape and place it where the reflection is?

I am currently working on an assignment using Tanagrams. I have the information that I have: • 2 large, and congruent, isosceles right triangles • 1 medium isosceles right triangle • 2 small, and congruent, isosceles right triangles • 1 square • 1 parallelogram The pieces can be...

So if any two points are congruent, what does that tell me about how any translations or rotations can equal reflections?

Could we say that B1 and B2 are congruent?

Triangle B2, A',O and triangle B2,A", O are congruent as well as there angles. Triangle A',B1, O and Triangle B1, A, O are congruent as well as there angles.

It can be said that they are the same and all the angles are equal?

Thank you!

I am currently working on a task involving isometries. I am confused as to how to explain the next two tasks to my adviser. B. Any combination of isometries can be accomplished with one of the four fundamental isometries (i.e., translation, reflection, rotation, or glide reflection). Provide...

So the answer would be 1/8?

So I would do A= (1/2)(√2/4)Sin(135) ?

My parallelogram has two pairs of parallel sides so which sides am I using?

Yes, Angle E and K are 45 degrees, and angles h and g are 135 degrees.

I am working on a task right now. I am currently trying to find the area of a parallelogram. I do not have the height. I only have the dimensions. I have tried suggestions like dividing the parallelogram into triangles and doing 1/2bh. The dimensions I have are the 1/2,1/2,\sqrt{2}/4...