Recent content by JoanF

You got the same I got Yes I'm sure ...

it is log3(x2 - 5x + 6) - log2(2 -x) = 2

Homework Statement Find x: log 3 (x^2 -5x+6) - log 2 (2-x) = 2 Homework Equations The Attempt at a Solution I tried and got: (3-x).[(2-x)^1-log 2 (3)] = 9 but I don't know how to get x here ...

x(t)=Asin(wt+Q) x(0)= -A -A=Asin(w.0+Q) -1=sin Q sin (-pi/2)=sinQ Q= -pi/2

oh ok, now I understand many thanks, really!

so the in spite of in 2nd case there are 2 forces acting, that doesn't change anything, right?

using g=10, I got: h=1,64 m using g=9,8, I got: h=1,4456 m I've done just like you

f= 1/T so is C) ?

I think is C) because the frequency is a characteristic of the oscillator. I think that D) is also correct because we change the position of oscillator and in the second case there are 2 forces: grav force and elastic force, in the first case there is only elastic force.

Homework Statement mass of the body=m Horizontally, the spring is deflected from its equilibrium position and then released, oscillated with a frequency f. Then, the same spring and the same body are suspended vertically, as in figure. Which one is correct? A) The frequency of...

Is it correct??

But why Q= -pi/2 it's wrong? I don't understand :S

Homework Statement mass of A=5,0kg mass of B=2,0kg friction coefficient between A and the plan=0,30 The system is moving with an acceleration of 7,5 m /s^2 and the angle theta is constant and equals to 37º. Then, a mechanism makes the body A and the body B stops. B stop when it is in...

I've done this:

1) A is the minimum height that a body of 1,0 kg must be abandoned to describe the circular path of the figure. We know that there is friction ONLY between A and C and that the circular path has radius 1,0 m. 1.1) The normal reaction in C is... A) 50 N B) 40 N C) 10 N D) 60 N (I had...