Recent content by Johnnnnnnnn

But I thought second order linear differential equations are in the form of y'' + p(x)y' + q(x)y = g(x), where q(x) would be 0 in this case. I'm guessing you mean that it's unnecessary to change v into y' as it just complicates the calculation?

So after seeing the derivation of sinking motion, I was wondering if this method of derivation is also correct. Since ##F_{\rm net} = ma = mg'- bv ##, ##a = g' - (b/m)v## From here, could I set a = d2y/ dt2, and v = dy/dt, letting y be the vertical distance the object travels, and use second...

Oh I see... Thanks for the help!

Hi guys! I am currently learning about fluid dynamics, and I am stuck on a certain equation derivation. It's about sinking motion which considers only gravity force, buoyant force, and viscous resistance. The link attached has the details...

Yes the ramp was a straight line. To be exact it was made up with two metersticks. So i placed wooden blocks in the top and bottom part between the two metersticks, taped it. So there would be a 15cm ish gap where the bigger radius part of the disk was rolling (without touching any surface...

By constant slope you mean that the top end of the ramp was at a same height? Then yes. When the disc rolled, the ramp didn't shift at all and stayed the same way it was.

I know I'm late, but thanks a lot! I now understand the reason behind the acceleration in the apparatus. Could you check if my calculations are correct? I tried fixing it accordingly. ***The calculations are for the section where the shaft, attached by disks in the center, is the surface that...

http://www.animations.physics.unsw.edu.au/jw/rotation.htm#rolling I have set up an apparatus similar to what the above link says (the first bit about brass object with shaft). So basically, the shaft is in contact when the brass is first rolling, then it suddenly accelerates when the edge of...