power in= 1350,000,000 kJ/h
power out= 540,000,000 kJ/h
so the difference is 810,000,000 kJ/h.
I guess what I am confused about is the answer they are asking for .They are asking for the rate in which heat must be rejected? What is that exactly?
Thanks.
Is there an equation I should be using?
I used 1350*10^6 kJ/h * rate=150 MW
rate=150 MW/1350*10^6 kJ/h
and since 1350*10^6 kJ/h= 0.00375 MW
rate=150 MW/0.00375 MW
=40,000
Is this right? Seems too simple. Plus what would be the rate? 40,000 MW per hr?
Homework Statement
An electric power plant produces 150 MW of power. If the coal releases 1350 × 106 kJ/h of
energy, determine the rate at which heat must be rejected from the plant.
Homework Equations
The Attempt at a Solution
So I am confused by what they are asking. So the...
Homework Statement
If the calorific value of wood is 16 MJ/kg and a match weights approximately 0.17 g, then (a)
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Oh yeah. sorry I knew that. It was in my notes but I read it too quickly.
so I am kind of lost here. I know that 1 Btu is what will increase 0.454 kg of water 1 degrees.
Since I have approx .5 Btu of energy but 1 kg of water...
I don't know what formula to use...
Cp is for constant pressure. I copy and pasted it from a PDF lecture so it got jumbled up.
So thermal is heat already right?
As for the water, should i just assume it is 25 c since that is the standard. How would I convert Btu to C?
Homework Statement
Horseshoe Falls, one of the Niagara Falls, has a 53 m drop. Consider one kg of water that
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