Calculating the conversion of potential energy to thermal

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Discussion Overview

The discussion revolves around calculating the increase in temperature of water after falling from a height of 53 meters at Horseshoe Falls, assuming all potential energy is converted to thermal energy. The conversation includes aspects of energy conversion, specific heat capacity, and unit conversions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant calculates the potential energy of 1 kg of water falling 53 m to be 519.4 J and converts this to BTU.
  • Another participant confirms the assumption that the kinetic energy of the falling water is used to heat that specific kg of water.
  • There is a discussion about the meaning of Cp, with one participant clarifying it stands for constant pressure and is related to the heat capacity of water.
  • Participants discuss the need to determine the change in temperature without assuming an initial temperature for the water.
  • One participant expresses confusion about how to relate BTU to the temperature increase of 1 kg of water.
  • Another participant calculates that 2.20264317 BTU is needed to increase 1 kg of water by 1 degree Celsius and estimates the temperature increase based on the available energy.
  • There is a suggestion to use SI units and look up the specific heat capacity in Joules for clarity.

Areas of Agreement / Disagreement

Participants generally agree on the approach to calculate the temperature increase but express differing views on the calculations and conversions involved. The discussion remains unresolved regarding the exact temperature increase due to variations in calculations.

Contextual Notes

Participants mention the need for clarity on unit conversions and the specific heat capacity of water, indicating potential limitations in their calculations. There is also uncertainty about the assumptions made regarding the initial temperature of the water.

jongood
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Homework Statement



Horseshoe Falls, one of the Niagara Falls, has a 53 m drop. Consider one kg of water that
falls over the falls. If, upon hitting the bottom of the falls, all of the water’s potential energy
is converted to thermal energy and this heats the fallen water, calculate the increase in the
water’s temperature.

Homework Equations



Ek = ½ m v2
PE = m x g x h

Thermal: change in Eth = m Cp change in T.


The Attempt at a Solution



So I should be calculate the potential energy of 1 kg of water falling 53 m. Then that that number and convert it to thermal energy. Use the thermal energy number to calculate the change in water temperature?

I calculated the potential energy to be 519.4 J.
Convert Joules to BTU=
519.4 joules = 0.492296212 btu

Now to calculate the increase in the water's temperature, I am not sure if that's the whole fall? I don't think that is possible since the amount of water is always changing. Now if they are talking about the increase in temp of that 1 kg of water... then i have no idea...

Am i on the right track? Thanks
 
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Yep, sounds like we assume that the kinetic energy of that particular kg of water is used to heat just that bit.

You quoted a formula:
Thermal: change in Eth = m Cp change in T.
What does Cp stand for?
 
Cp is for constant pressure. I copy and pasted it from a PDF lecture so it got jumbled up.

So thermal is heat already right?

As for the water, should i just assume it is 25 c since that is the standard. How would I convert Btu to C?
 
Actually Cp is the heat capacity of water - it's a number that says how much Joules you need to heat 1 kg of water by 1 degree Kelvin (or celsius) - look it up!.

You don't need to assume any temperature, the formula says "change in T", right? Well, that's exactly what you're asked for.
 
Oh yeah. sorry I knew that. It was in my notes but I read it too quickly.

so I am kind of lost here. I know that 1 Btu is what will increase 0.454 kg of water 1 degrees.

Since I have approx .5 Btu of energy but 1 kg of water...

I don't know what formula to use...
 
If 1 Btu will increase 0.454 kg of water by 1 degree, then how many Btu do you need to increase 1 kg of water by 1 degree?
 
2.20264317 Btu will be needed. but since I only have .454 Btu, then the water will only increase by approx. .25 degrees C?
 
I got a slightly different number, but yes - that is the idea.

If you want to use the internationally accepted SI units rather than the weird British units, you could look up Cp in a standard resource and use the value in Joules :D
 

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