Recent content by JoshMP

Homework Statement 1. If you looked at the spectrum of a reflection nebula, would you see absorption lines, emission lines, or no lines? Explain your answer. As part of your explanation, describe how the spectrum demonstrates that the light was reflected from nearby stars. Homework...

Homework Statement A 20 kg child is on a swing that hangs from 3.0-m-long chains. What is her maximum speed if she swings out to a 45 degree angle? Homework Equations KE= 1/2mv^2 Ug= -mgy The Attempt at a Solution I tried to use conservation of energy to solve this problem...

So for the car, the free body diagram has gravity pointing down, normal force pointing up, 4000N pointing in the direction of motion, and the force from the truck pushing back on the car pointing in the opposite direction of motion. For the truck, gravity pointing down, normal force pointing...

Homework Statement A 1000kg car pushed a 2000kg truck. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N. What is the magnitude of the force of the car on the truck? What is the magnitude of the truck on the car...

My FBD consists of Gravity pointing down, normal force pointing down, and static friction pointing up. (The net force along the radial axis is equal to Gravity + Normal force - static friction. This net force is equal to the mass multiplied by the radial acceleration, which = v^2/r. Using...

I'm stuck. I've got an inequality set up, but I can't isolate the velocity. Am I even on the right track?

Wouldn't that mean that the normal force at the top is equal to the normal force at the bottom? If the net force is the same at the top and bottom, and gravity is the same too, then the normal force must also be the same, and the ratios would be the same too.

Ok I got the ratio at the bottom correct. But I'm having trouble with the top. My FBD has gravity pointing down and normal pointing down (is that right? - it's a Ferris wheel...). When I solve for the normal force, I get a negative value, which is impossible!

Up? I thought friction points tangential to circular motion?

The normal force is what keeps people from falling- when the veolcity decreases such that the normal force is less than 0, the people would fall off the ride. My FBD has gravity pointing down, normal force pointing down, and friction pointing to the left.

Ok tell me if I'm on the right track. I know that the radial acceleration is 0.95 m/s^2, which means that the net force is pointing down at the top of the wheel and up at the bottom. I use this net acceleration and solve for Fnet. Does this value of Fnet = the apparent weight?

Radial acceleration. Got it, thanks. So what about the ratios of weight...would they just be 1 to 1?

Homework Statement While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find the motion somewhat unpleasant. To take your mind off your stomach, you wonder about the motion of the ride. You estimate the radius of the big...

Homework Statement In an old-fashioned amusement park ride, passengers stand inside a 5.5m-diameter hollow steel cylinder with their backs against the wall. The cylinder begins to rotate about a vertical axis. Then the floor on which the passengers are standing suddenly drops away! If all...

The edge of the ramp is 50 m high. The edge of the ramp *is* the cliff. I got 2.63 for ax by setting (Fnet)x equal to the x coordinate of Thrust. Thrust=200 N, so Thrust(x)= 200 cos 10=197=m*ax. Ergo ax=2.63 m/s^2. The part while he is on the ramp cannot be calculated since no...