Recent content by Jotun.uu

Yeah. Having a positive expression for time did always sit better with me as well ;)

Thank you so much for your answer. Makes perfect sense. I knew i was not crazy! I will report this discrepancy to my teacher post haste =)Edit: Are you sure you are susposed to reverse ln(p(p0)? Is it to get rid of the minus sign? Because -ln(p/p0) = ln( (p/p0)^-1 ) ??

(Bump). I Really do need an answer to this!

Homework Statement A sphere is filled with a gas which has a constant temperature T. The pressure in the sphere starts at p0 and the spheres radius is r. Assume that a small area (A) of the sphere is held at a very low temperature, while the rest of the surface holds the temperature T. Also...

I believe that Newtons II law is Eulers I law btw.

From wikipedia: "Euler's second law states that the sum of the external moments about a point is equal to the rate of change of angular momentum about that point." Common usage is Moment = I*alpha

Homework Statement A billiards ball (mass m) is hit by a billiard stick on the center of the ball (from the side) with a collision impulse mv0 so that the cues line of travel goes straight through the center of mass of the billiards ball, which in the collision-approximation gives a speed v0...

[pulley] = Radius R, and moment of inertia I = (1/5)mR². [weights] = A = m and B = 2m. [string tension] = left side (A): T ; right side (B): S. [gravity] = As always g denotes the pull of the Earth (9.82 m/s² here in Sweden). The (all new!) attempt at a solution So, as listed above I...

I think so.. but I'm not a pro or anything, just a lowly student.

then the acceleration of B must of course be negative! thanks! So the new NII for B is: S - 2mg = -2ma Gah! stupid mistake! I misinterpreted some old notes of mine. Of course alpha = a/R! I am heading out to a wedding now (my girlfriends sister is getting married) I will be sure to...

We don't need Xo in our equations because the distance (8900m) up until the final stretch of 1100m doesn't matter. the only thing that matters is the initial velocity, the remaining distance, the acceleration and the time needed.

180*a*t3 is not equal to 180a + 180t3 [[a*b*c IS NOT a(b+c)]] in the same way that if example: 2*3*4 = 24 while 2*3 + 2*4 = 6 + 8 = 14

using 180 instead of 3 will only make it so that the answer will be in seconds instead. my final equation would then be t² - 360t = (360v-2s)/a

but if you work hard on something you remember it a lot better =)

I get that you summed the forces along the x-axis to be positive 50 000N in the positive direction and the friction as -5000N, so I'm no expert but that should be right. However shouldn't the engines weight be added to the mass (20,000+5000 kg) * a ? I reckon this has to be wrong although...