Recent content by jsalapide

Is it possible for the critical angle to exist when light goes from water (n=1.33) into glass (n=1.5)? I solved this using snell's law. and my answer is no.. because glass has greater refraction index than water. And when you use snell's law and solve for the critical angle, there will be no...

Is it possible for the critical angle to exist when light goes from water (n=1.33) into glass (n=1.5)? My used the formula sin(critical angle) = n1/n2. I'm a bit confused, should the numerator(n1) always be less dense compared to the denominator(n2).

I solved for the critical angle and I got 56.44 degrees, Should the answer be "greater than 56.44 degrees" so that the total internal reflection may occur?

If the transparent material has an index of refraction of 1.2, what is the angle of incidence beyond which total internal reflection occurs?

I've used it before, but the index of refraction is not given. Should I assume that the index of both material are equal?

Light strikes the surface of a transparent material at an angle of incidence of 30. If the refracted angle in the transparent material is 20, what is the speed of light in the material? Is it possible to solve this problem without their index of refraction? If possible, how?

two converging mirrors A & B, having focal lengths 12 cm and 4 cm respectively, are facing each other and 36 cm apart on a common principal axis. A plastic sword is placed vertically upward in front of mirror A at a distance of 18 cm. Locate and describe the nature, orientation and size of the...

A plane mirror is placed on the level bottom of a swimming pool, which holds water to a depth of 3 m. A swimmer is located 2.0 m above the mirror. An observer above the water looks vertically downward at the swimmer and its image in the mirror. What is the apparent difference in depth between...

Ah.. my theta is the angle between the plane of the coil and the field anyways,, thanks.. how about the unit? Is it web-A?

A circular coil of 50 turns has a radius of 0.2m and carries a current of 5A. The coil is in a field where the magnetic induction is 0.6 Web/m^2. What is the max torque on the coil? I used the formula for the torque on a coil: r=NBIAcos(theta) I assume that the angle for max torque is 0 my...

i come to think of it, the image size does not change no matter what value of p and q is. could that mean that there is no way that the image will be 2.5 times greater than the object?

i only know the equation on how to solve for the focal length f= (pq)/(p+q) where p is the distance of the object from the mirror and q as the distance of the image from the mirror.

Where do you put an object in front of a concave mirror of focal length 10 cm to produce an image that is inverted and 2.5 times greater than the object? I have no idea how to solve this.. help..

ok sir, thanks for the time..

ok, the first image was 6m. but how do you get 14m for the second image? I assume that the distance of the second image is 14 m if the woman is facing at the mirror 7m away from her. But what if she is facing the mirror which is 3m away from her? could the second image still be 14m?