Position Object for Inverted, Magnified Image with Concave Mirror

AI Thread Summary
To produce an inverted image that is 2.5 times larger than the object using a concave mirror with a focal length of 10 cm, the object must be positioned at a specific distance. The equation f = (pq)/(p+q) relates the object distance (p) and image distance (q) to the focal length (f). Image size is directly influenced by the object distance, meaning it can change as the object is moved. The assumption that image size remains constant is incorrect; varying the object position will alter both the image size and location. Proper calculations and adjustments are necessary to achieve the desired image characteristics.
jsalapide
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Where do you put an object in front of a concave mirror of focal length 10 cm to produce an image that is inverted and 2.5 times greater than the object?

I have no idea how to solve this.. help..
 
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What are the basic equations describing spherical mirrors and image formation?
 
i only know the equation on how to solve for the focal length

f= (pq)/(p+q)

where p is the distance of the object from the mirror and q as the distance of the image from the mirror.
 
Good. And how does image size relate to p and q?
 
i come to think of it, the image size does not change no matter what value of p and q is.

could that mean that there is no way that the image will be 2.5 times greater than the object?
 
jsalapide said:
i come to think of it, the image size does not change no matter what value of p and q is.
You'd better check that assumption. As you move the object around, the position and size of the image will change.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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