ELECTROMAGNETISM-torque on a current coil

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The discussion centers on calculating the maximum torque on a circular coil with 50 turns, a radius of 0.2m, and a current of 5A in a magnetic field of 0.6 Web/m^2. The initial formula used for torque was r=NBIAcos(theta), assuming the angle for maximum torque is 0 degrees. However, clarification reveals that the angle should be defined as the angle between the area vector of the coil and the magnetic field, where maximum torque occurs at 90 degrees. The correct torque calculation involves using the formula μ X B = NIAB sin(theta). The standard unit for torque is Newton-meter, which is equivalent to web-A.
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A circular coil of 50 turns has a radius of 0.2m and carries a current of 5A. The coil is in a field where the magnetic induction is 0.6 Web/m^2. What is the max torque on the coil?

I used the formula for the torque on a coil: r=NBIAcos(theta)
I assume that the angle for max torque is 0
my answer is 6pi..

is that right?
is it ok to let the angle be 0??
 
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Looks OK to me.

I'm not sure how you defined your angle theta. Usually it's defined as the angle between the area vector (normal to the plane of the coil) and the magnetic field, in which case the torque is given by μ X B = NIAB sin(theta). Using that definition, the torque is maximum when theta = 90 degrees.
 
Ah.. my theta is the angle between the plane of the coil and the field

anyways,, thanks..

how about the unit? Is it web-A?
 
jsalapide said:
how about the unit? Is it web-A?
The standard unit for torque is Newton-meter (which is equivalent to web-A).
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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