Position Object for Inverted, Magnified Image with Concave Mirror

Click For Summary
SUMMARY

To produce an inverted image that is 2.5 times greater than the object using a concave mirror with a focal length of 10 cm, the object must be positioned at a specific distance from the mirror. The fundamental equation governing this scenario is the mirror formula: f = (pq)/(p+q), where p represents the object distance and q represents the image distance. The relationship between object distance, image distance, and magnification must be understood to determine the correct placement of the object.

PREREQUISITES
  • Understanding of concave mirrors and their properties
  • Familiarity with the mirror formula: f = (pq)/(p+q)
  • Knowledge of magnification in optics
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the derivation and application of the mirror formula in optics
  • Learn how to calculate magnification using the formula: Magnification (M) = -q/p
  • Explore the behavior of images formed by concave mirrors at various object distances
  • Investigate practical applications of concave mirrors in optical devices
USEFUL FOR

Students of physics, optics enthusiasts, and anyone involved in the study of image formation using concave mirrors will benefit from this discussion.

jsalapide
Messages
39
Reaction score
0
Where do you put an object in front of a concave mirror of focal length 10 cm to produce an image that is inverted and 2.5 times greater than the object?

I have no idea how to solve this.. help..
 
Physics news on Phys.org
What are the basic equations describing spherical mirrors and image formation?
 
i only know the equation on how to solve for the focal length

f= (pq)/(p+q)

where p is the distance of the object from the mirror and q as the distance of the image from the mirror.
 
Good. And how does image size relate to p and q?
 
i come to think of it, the image size does not change no matter what value of p and q is.

could that mean that there is no way that the image will be 2.5 times greater than the object?
 
jsalapide said:
i come to think of it, the image size does not change no matter what value of p and q is.
You'd better check that assumption. As you move the object around, the position and size of the image will change.
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K