Recent content by jumi

Thanks for the replies. So what exactly should I do? Are the formulas tms posted correct?

Homework Statement Using 5 different ammeters, you get the following data (all measured in Amps): I_{A} = 128 ± 2 I_{B} = 121 ± 1 I_{C} = 114 ± 8 I_{D} = 120 ± 3 I_{E} = 122 ± 4 Calculate the mean current and the standard deviation of the mean. Homework Equations Standard...

Ok, I have this circuit, and I'm trying to devise a way to create an 8x8 matrix for any given combination of target qubit and controlled qubit. (I is the identity matrix, and X is the CNOT operator) I want it to also include the qubit that passes through untouched because I'm trying to...

I don't understand how I could just go from (1) and (2) to (4)... Or why the numerator doesn't have a vector magnitude, whereas the demoninator does... I was, however, able to get the correct answer, just not using the full notation from equation (1). So I start with...

So there's this situation going on: http://imageshack.us/a/img826/7398/physicsforums.png Going from the definition of an electric field: (1) [SIZE="5"]\vec{E} ( \vec{x} ) = \frac{1}{4\pi\epsilon_{0}} ∫ \frac{\vec{x} - \vec{x'}}{| \vec{x} - \vec{x'} | ^3} ρ( \vec{x'}) d^3x' (2) The...

I don't follow how this expression makes it easier: \langle x_{\pm} | = | x_{\pm} \rangle^{ \dagger } = \left( \frac{|0\rangle \pm |1\rangle}{\sqrt{2}} \right)^{ \dagger } = \frac{|0\rangle^{ \dagger } \pm |1\rangle^{ \dagger }}{\sqrt{2}} = \frac{\langle 0 | \pm \langle 1 |}{\sqrt{2}}

Thanks so much! I really appreciate all the help.

Oh, alright, I get it now. Disregard that second statement. I knew the complex conjugate showed up in some capacity, but you answered it in your first sentence. So all in all (sorry for continually pestering you...), I would take [SIZE="3"]\left|x_{+}\right\rangle =...

Ok, I had a chance to review the math a bit. So knowing, P(\alpha) = | \langle x_{\alpha} | \psi \rangle |^2 = \langle x_{\alpha} | \psi \rangle ^* \langle x_{\alpha} | \psi \rangle = \langle \psi | x_{\alpha} \rangle \langle x_{\alpha} | \psi \rangle, I can simply multiply the row vector...

Ok thanks, it's starting to piece together a little better now. I'll definitely give that book a read. So we can't say say |\alpha_{00}|^2 and |\alpha_{01}|^2 sum up to equal 1 since they were only 2 of the 4 options in the original function. But we CAN say that for the second measurement...

I'm actually an Engineering Physics major. Never taken a QM or probability course, either. Currently a junior. We're using "Quantum Computation and Quantum Information" by Nielsen and Chuang. I understood mostly everything in your first post. However, it seems like you just took a leap to...

Awesome reply, thanks. I don't have time to really sit down and mess around with the math tonight, but I'll take a look at it tomorrow and see what I can come up with. I'll make another reply if I'm still having trouble. Otherwise, I really appreciate the help. Thanks.

Ok, thanks. Yeah, I can see and reproduce the pattern, but I was wondering "why". No worries, though; I appreciate your help.

Ok, I understand that. However, in class, we did something like this: Say we have the same 2-qubit state we've been talking about, \left|ψ\right\rangle = \alpha_{00}\left|00\right\rangle + \alpha_{01}\left|01\right\rangle + \alpha_{10}\left|10\right\rangle +...

Sort of. How exactly does the operation \langle \psi | x_{\alpha} \rangle \langle x_{\alpha} | \psi \rangle work? (P.S. Maybe I should have mentioned in the beginning (and I'm not sure if that's relevant here), but I've never had a full Linear Algebra course.)