When I apply that force, I get 24mm of deflection, a Max Stress of 2791 MPa, which would mean my F.S. is .06. So the cross beam will be bent significantly?
This is not homework. I did try the spring method you suggested and got the following:
##KE = PE, (.5(4.082kg)(15.24m/s)^{2})/x = .5(1.588 \times 10^{6} N/m)(x^{2}), x=.084 m##
Then I applied that distance to the spring constant and found my force to be ~133422N. This seems quite high for...
I did a beam bending calculation on the cross beam, but I am unsure of what size force to apply. Is there a range you'd suggest? I started with a load of 214 lbf (950 N), and found that the beam will deflect .0235" (.5981mm). The impact location is also the direct center of the cross beam (974mm/2).
What is the correct way to calculate the impact force of a 2"x4" flying through the air and hitting a solid cross beam? The knowns are:
Velocity: 50 ft/sec
Distance To cross beam: 12 ft
2" x 4" Weight: 9 lbs
I don't know much the cross beam will deflect on impact, so the stopping distance is...