Recent content by Kanchana

G/[G,G] is abelian and x,y are from G/[G,G]. Then [x,y]=1..?

If the group G/[G,G] is abelian then how do we show that xyx^{-1}y^{-1}=1? Thanx

Let H be a normal subgroup of G. Then factor group G/H is an abelian subgroup. For x, y not in H xHyH=yHxH and xyH=yxH (xyH)(yxH)^{-1}=id xyx^{-1}y^{-1}=id Are these steps correct? thnx