Recent content by Karajovic

hey sorry, problem 2

okay, well i get f1 = (M+m)a while F2 = ma and F1-F2 = Ma + ma - ma = Ma and f1 does not equal f2 because f1 = (M+m)a while F2 = ma, if they equal, no movement would occur! How's that :biggrin: it makes sense now! The total net force of the system is F1, therefore the acceleration of the...

Okay, thank you! But may I ask, the net force is just f1 then? You do not subtract f2 from it :confused: and is my b) statement still okay?

yes, but f1 does equal Ma. but for c) doesn't the F2 force sort of act like a frictional force to the F1 force? Like its a reaction force, but it pushes against the box with f1, so the net is f1 - f2, or not? oh, sorry then :/ what i meant is the acceleration of the system... so a = F1/(M +...

F1 has to equal Ma ? That is the force exerted on the big box, of mass M. :confused: and for c) its asking for the net acceleration, right? So isn't that equal to Fnet/mnet, Fnet equals (F1 - F2 (because F2 is the force hitting the little box by the big, but then an equal force hits the big...

hey, here's a good textbook that has a similar problem: http://www.scribd.com/doc/24324123/McGraw-Hill-Ryerson-High-School-Physics-12-v2 page 68, but in your case, instead, you will have to go backwards and solve for the veloctiy, I believe. Sorry I couldn't write it all out, I don't have...

Okay so my conclusion: b) F1 does not equal F2. First of all F1 = Ma while F2 = ma, also, if the forces were equal, the boxes would not be moving c) anet = (f1-f2)/(M+m) d) F2 = ma now for e) I'm not sure.. F1 = Ma while F2 = ma... Now how do I use different values of M and m? I don't seem to...

Thank you very much!

[Solved] Kinematics ratio problem Homework Statement A force F produces an acceleration a when applied to a certain body. If the mass of the body is doubled and the force increased five-fold, what will be the effect on the following? a. its acceleration b. the distance the body travels in...

Oh! I apologize, yes, know I understand! You can still use sin, but since the angle is with the vertical you would subtract it by 90 to get your horizontal angle.. so sin(90-x) = cosx (x is with the vertical) ? Thank you! :smile:

Haha, you're right :-p Then how would I use two forces in one equation? Because for ii] you have F1 = Ma (acting on the M box) and you have F2 = ma (also acting on the M box)...

Argh... I don't get it... So, if you are given an angle with the horizontal, you use sin (but you said this is the vertical?) and if you are with the vertical, you use cos (which you said is the horizontal?) What do you mean by the angle between the force and the direction? (I put an...

Okay.. so I would get: i] F = F1 + F2 (?) ii] F1 = Ma iii] F2 = ma I don't know if that's it :confused: Thanks for your time.

Hey tiny-tim! Thanks so much! I've been trying to find a solution for a while now! But may you please explain why you use cos? Thanks again! (and I thought I replied to the other thread, but I guess it didn't send, I'll post there now!

Homework Statement A hang-glider, diving at an angle of 57.0o with the vertical, drops a water balloon at an altitude of 680.0 m. The water balloon hits the ground 5.20 s after being released. a. What was the velocity of the hang-glider? Homework Equations The Attempt at a Solution...