Recent content by KayDee01

  1. K

    Barometric law for hard sphere sedimentation

    So I have the equation for Barometric law in terms of density as: \frac{\phi(z)}{\phi_{0}}=exp(-g.M.z/R.T) where R=Universal gas constant, z=height of sedimentation, T=Standard temperature, g=Gravitational acceleration, M=Molar mass. When this equation is used to calculate the height of the...
  2. K

    How Can dI/dV Help Determine Fermi Level and Band Gap in Semiconductors?

    I'm supposed to be working with an STM in the coming weeks to determining the Fermi Level of some semiconductor diamond films. I was bombarded with a lot of information by my lab supervisor and the bit of my notes about the calculation just says "Differential of voltage vs current allows us...
  3. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    Using that definition of \overline{u} I got them to equal one another :) Problem solved! And thanks for the warning about double posting, I won't be doing that again.
  4. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    I did this integral and got \frac{1}{2}a^{2} which doesn't equal \overline{x}.\overline{y} as I am trying to prove. The double integral will always eliminate the variables x and y from the equation. But \overline{x}.\overline{y} has the variables in it. How do I overcome this?
  5. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    I see me mistake with \overline{y}, the x shouldn't be squared right? If d(x,y)=xdy+ydx. Surely I end up with \int{xy.f(x,y)d(xy)}=\int{x^{2}y.f(x,y)dy}+\int{xy^{2}.f(x,y)dx} And I still can't get that to equal \overline{x}.\overline{y}
  6. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    I tried \overline{xy}=\int^{∞}_{-∞}{x.y.f(x,y)dx} =\int^{a}_{0}\int^{a}_{0}{x.y.6a^{-5}xy^{2}dx} =\int^{a}_{0}\int^{a}_{0}{6a^{-5}x^{2}y^{3}dx} =\frac{1}{2}a^{2} which does not equal \overline{x}.\overline{y}
  7. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    I tried \overline{xy}=\int^{∞}_{-∞}{x.y.f(x,y)dx} =\int^{a}_{0}\int^{a}_{0}{x.y.6a^{-5}xy^{2}dx} =\int^{a}_{0}\int^{a}_{0}{6a^{-5}x^{2}y^{3}dx} =\frac{1}{2}a^{2}=/=\overline{x}.\overline{y}
  8. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    Sorry, I submitted the question to early and had to add the rest of the problem. I'm not sure what the \overline{xy} integral should look like.
  9. K

    Can Independence Simplify Calculating Expectation Values in Probability?

    Homework Statement f(x,y)=6a^{-5}xy^{2} 0≤x≤a and 0≤y≤a, 0 elsewhere Show that \overline{xy}=\overline{x}.\overline{y} Homework Equations \overline{x}=\int^{∞}_{-∞}{x.f(x)dx} The Attempt at a Solution \overline{x}=\int^{∞}_{-∞}{x.f(x)dx} =\int^{a}_{0}{x.6a^{-5}xy^{2}dx}...
  10. K

    Nabla calculus and conservative forces

    1. The problem statement I'm trying to show that the magnetic force is only conservative if dB/dt=0 Homework Equations F=q[E+(v\timesB)] Conservative if ∇\timesF=0 ∇\times(A\timesB)=A(∇\cdotB)-B(∇\cdotA)+(B\cdot∇)A-(A\cdot∇)B Maxwells equation: ∇\timesE=-∂B/∂t The Attempt at a Solution...
  11. K

    Tensor Equations for Anisotropic Materials

    Hi, I am in the middle of revising for and a classical electromagnetism exam, and I've hit a wall when it comes to tensor equations. I know that for anisotropic materials: J=σE and E=ρJ And that in component form the first equation can be written as J_i = σ_{ij} E_j What I'm wondering...
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