Recent content by kayleech

Thanks! That worked.

Yes... but I still don't know where to go from there. I did v=square root of [((kx^2 - 2mgy + (Fthrustxy))/m] x=0.2584m y=0.194m I don't think that makes sense, seeing as how it was the wrong answer.

I'm not exactly sure how I would go about adding that into the energy equation though.

Homework Statement A 10.6 kg weather rocket generates a thrust of 226.0 N. The rocket, pointing upward, is clamped to the top of a vertical spring. The bottom of the spring, whose spring constant is 402.0 N/m, is anchored to the ground. Initially, before the engne is ignited, the rocket...

I did that and I came up with SO32- being the only answer. Is that correct or am I doing something wrong?

Hi, I'm having trouble figuring out which of the following molecules can be described using three charge-minimized resonance structures. Does anyone have any idea which molecules this would include? a. SF4 b. SO3 c. SO32- d. HSO4- e. SO2+

I figured it out using this website: http://www.rit.edu/~uphysics/uncertainties/Uncertaintiespart2.html#mixtures . Thanks.

I'm confused how to even use that equation though!

These are my measurements: D1 = 5.381 +/- 0.001 cm D2 = 2.070 +/- 0.001 cm t = 0.304 +/- 0.005 cm m = 40.04 +/- 0.005 g I then calculated the uncertainties of D1 and D2 squared: D1^2 = 28.95 +/- 0.01 cm^2 D2^2 = 4.285 +/- 0.004 cm^2 D1^2 - D2^2 = 24.67 +/- 0.01 cm^2 Up until there...

Actually, hold on. I'm getting 965.10 m/s^2.

AHH THANK YOU! For the first one, I kept forgetting to add the two displacements together. And for the second one, it should have been positive! THANKS AGAIN!

FOR THE PARACHUTIST QUESTION: I got 31.02m/s as Vf for the first segment: Vf^2 = Vi^2 +2ad where Vi = 0 m/s, a = 9.8 m/s^2, and d = 49.1 m but when I tried using that for the second part, I got the wrong answer. I got an answer of 248.39 m from: displacement = (2.90^2 - 31.02^2) /...

I need the time for the acceleration... I tried and I got 3.02s, but that didn't work out in my equations that followed. The second part of the fall... wouldn't be 0.453m? I tried using the equation I stated above with -9.8m/s^2, but that didn't work. I also tried adding the two heights...

Homework Statement A very silly person, intent on catching pigeons on the roof of an apartment building, trips and falls a distance of 44.6 m. She lands on a metal garbage can, crushing it to a depth of 0.453 m and walks away without having been hurt. What acceleration did she experience...

Homework Statement A baseball player is running with the ball and throws it to first base in an attempt to get the runner out. Describe the considerations the player must take into account in order to be successful. Include the concepts of projectile motion and relative motion principles...