Recent content by Khemkhajon

Homework Statement A 500.0-g iron bar at 212 C is placed in 2.0 L of water at 24.0 C. What will be the change in temperature of the water ( Assume no heat is lost to the surroundings.)Homework Equations (Mass of substance)(Specific Heat of substance)( Change in Temp)The Attempt at a Solution I...

Yea positive. Checked it twice that's why I was confused. Maybe I have to know the speed of sound through Air?

Homework Statement Dogs are able to hear mucher hgher frequencies than humans are capable f detecting. For this reason, dog whistles that are inaudible to the human ear, can be easily heard by a dog. If a dog whistle has a frequency of 30,0000 Hz, what is the wavelength of sound emitted...

o ok so like if I pull a rock and doesn't move but keep increasing my force of pull it will overcome the maxium force of static friction. but I am confused sort of because max friction must be overcome. but i that example arent we just increasing our force to overcome the max friction. Isnt the...

I thought static friction was always at its maximum, because I know That static friction force must be overcome by an applied force before an object will move. The maximum possible friction force between two surfaces before sliding begins is the product of the coefficient of static friction so...

Also can someone not just tell answer but explain please.

1. Describe a situation where you were dealing with static friction that wasn't a maximum Im getting stuck on this question. Cause i can't think of a situation please some help would be appreciated

o ok thankyou

so back to the question if its speed was negative and starts to slow down what would the a vs t be?

Think of it as ball rolling down a ramp. it starts at 50m-----------ends at 0m

Thats not true. Because if they gave you a x vs t graph of a object heading towards the orgin and speeding up the acceleration would still be negative because of the slope

If a object was heading towards the orgin while slowing down. How would the a vs t graph look. I keep thinking it would be a positive acceleration line, but I am not sure wondering if anyone could clarify