hmm, the .063 is the specific heat of the copper sample? I don't know, I think we are thinking of two different concepts or whatnot. Thanks for all your help, I do appreciate it:approve:
The temperature of the copper before being put in the calorimeter was 103 Celsius. I believe we were to assume the water and metals to be the same temperature. The water in the calorimeter was 18.5 Celsius and 21 Celsius after thermal equilibrium.
Alright So I worked out the problem how you said.
mass of water is 242.3*3.4 which gives me 823.82 calories, multiplied by 4.184 which gives me 3445 joules. I plugged that into Q=mc delta T, 3445J=.07kg*C*1.8 celsius, which resulted in 27341 J/kg-degree celsius. I just want to be sure I'm doing...
So the change in temperature was Q? for instance one calorimeter started at 18.5 Celsius and we added the copper to it and it reached thermal equilibrium at about 22.1 Celsius so Q would be the change between those two? I'm a bit lost as to converting calories to joules because forgive my...
We weighed the 5 metals. We weighed the calorimeter cups with and without water. We heated a beaker of water with the metals in them to boiling. We placed the metals in the calorimeter cup one at a time until each reached thermal equilibrium. then took down the temperature. That's the extent of...
I'm pretty sure. We were supposed to use our findings to calculate the specific heat of the metals we tested. Yet I can't figure out how to find another specific heat. We are supposed to find the specific heat then compare it to the actual established specific heat of the metal and determine the...
Homework Statement Hello, I'm having some trouble with a lab report. I am supposed to find the specific heat of five metals but I don't know exactly how to use the equation correctly. for instance I have copper at 70.2g, the delta T at 1.8 degrees Celsius, specific heat of copper is 385...
Homework Statement Hello, this is my first time posting, I've run into a bit of a snag in my physics lab. I am to figure out the coefficient of friction based on the values we found in the lab. Now I found them out however I just want to be sure that I am doing this right. these values were...