Recent content by kiowaviator

  1. K

    Maximum Kinetic Energy of a Particle with Force F = F0e^(–kx)?

    Ok, that makes sense. I was there I just couldn't see it. Thanks all.
  2. K

    Maximum Kinetic Energy of a Particle with Force F = F0e^(–kx)?

    I did that, that's why the second term inside the brackets is 1/k, since e^(-k*0)=1.
  3. K

    Maximum Kinetic Energy of a Particle with Force F = F0e^(–kx)?

    This question is whooping me. I know I have the calculus part right I just don't know where to go from here? A particle moving along the x-axis is acted upon by a single force F = F0e^(–kx), where F0 and k are constants. The particle is released from rest at x = 0. It will attain a maximum...
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