I would like to say because, when a measurement is made, the wavefunction will collapse into one of the superposition eigenfunctions ##\phi_n## where the operator ##\hat{Q}## on ##\phi_n## will 'output' the eigenvalue ##Q_n##?
I see thank you - I think what threw me off was just the wording of the question (as this was the only question in a series of superposition question that involved the eigenvalues) and I expected to utilise more information than I needed.
On from that could you possibly recommend any resources...
I first Normalise the wavefunction:
$$ \Psi_N = A*\Psi, \textrm{ where } A = (\frac{1}{\sum {|a_n^{'}|^{2}}})^{1/2} $$
$$ \Psi_N = \frac{2}{7}\phi_1^Q+\frac{3}{7}\phi_2^Q+\frac{6}{7}\phi_3^Q $$
The Eigenstate Equation is:
$$\hat{Q}\phi_n=q_n\phi_n$$
The eigenvalues are the set of possible...
So Noether's Theorem states that for any invarience that there is an associated conserved quantity being:
$$ \frac {\partial L}{\partial \dot{Q}} \frac {\partial Q}{\partial s}$$
Let $$ X \to sx $$
$$\frac {\partial Q}{\partial s} = \frac {\partial X}{\partial s} = \frac {\partial...