Homework Statement
Homework Equations
CPU Time= Σ(individual IC time)
The Attempt at a Solution
What I did was first find the integer time, which is 100=75+X, and X is 25. To find the percent reduced,
I did 100(1-x)=75+25(1-0.5). This means x is 0.125 or 12.5 %.
Is this correct?
Thanks for the help. I think I understand the set up. The issue is when evaluating the integral, I get this:
Using the t>1 case, the integral becomes ∫(t-λ)*(1)⋅dλ , where x(t-λ)=(t-λ) and h(λ)=1. This is because the x graph is only valid when λ is between 1 and 0. Since t is between [1,2]...
Homework Statement
Homework Equations
y(t)=x(t)*h(t)=∫x(λ)⋅h(t-λ)⋅dλ
The Attempt at a Solution
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Is what I have the correct interpretation or or am I wrong?
Thanks
So I understand how to do the cross product. The problem is I don't know how to define ##\vec m## as an x and y components like B is = Boy(unit vector).
Thanks, for the comment. I still am a little confused. The angle between the magnetic field and moment would be 60 degrees correct? If so, how do I apply this for a torque vector
Homework Statement
Homework Equations
m=N*I*A
T=m X B
m = n(unit vector) *m
The Attempt at a Solution
To calculate m, I know it is just plugging in the information. Thus, m=0.8. Now, the question is computing the unit vector, which has me confused. Using the right hand rule, and going along...
If this is true, would the surface integral be drdΦ or dΦdz? I think it would be drdΦ since it is defined in radial and angular direction. The surface, I mean.
Thanks for the response. I am using cylindrical coordinates and since the point P is (0,0,z) and the disk is(r,Φ,0) doing the substraction is -r,-Φ,z whcih is the vector R'. The magnitude is then R'=√((-r)2+(-Φ)2+(z)2).
Homework Statement
Homework Equations
V=¼*(1/(π∈) * ∫(ρs/(R')*ds' where R' is distance from point to surface
R'=|R-Ri| distance from observation point to location of surface charge density.
The Attempt at a Solution
So my attempt was to define R' as R'=√((-r)2+(-Φ)2+(z)2). Then I said...