I have been sitting here trying to find which variable to choose, and which equation to try to work with the find t or v. There just seems to be an unknown variable too many in every one. I also wonder about the wording. I just need a hint to get started on this.
Homework Statement
Jill throws a Javelin by first accelerating it from rest through 85 cm and releasing it from a height
of 2.2 m at an angle of 35 degrees and it goes a distance of 62 m.
A) What are the values of the vertical and horizontal components of initial velocity?
B) Find...
Wow, it was so simple that I never even thought about it. I don't know how id made it through math 137 and still make that mistake. Thank you very much.
d/dt (pt) woud be (t)? correct? and d/dt (q(t^2)) would be 2qt? so my vector for velocity is V= (t)i + [(-10m/s^2)t]j?
Giving the vector A= [d/dt (t)]i + [d/dt (-10(t)m/s^2)]
what I can see:
1)The derivative of t would be 1, as with any lone variable?
2)the derivative of 10(t) is t...
Wouldn't the derivative of a be 0?
So then I can find that V= [(0m)+(t)]i + [(0m)-(t^2)]j
So V= (t)i + (-t^2)
Deriving V, I get that A= (1)i + (-2t)j ? I see my answer here is wrong as well... I really how no clue what I am doing wrong, and I can't even find deriving V and A from an R...
Isn't the derivative of 2, 1? I apologize, I thought you left variables in the equation until you were done deriving? As in I would put 2 in for t after I had the equation for acceleration?
Homework Statement
An object has a position given by r-> = [2.0 m + (1.00 m/s)t] i + [3.0m−(5.00 m/s2)t2] j, where all quantities are in SI units. What is the magnitude of the acceleration of the object at time t = 2.00 s?
Homework Equations
All I am thinking here is that I can find...