Recent content by Kpgabriel

So the Tension force would be equal to T= M*g - M*a and that is equal to 274.4N

No, I do not think it is. So I drew out the free body diagram and I got that the Tension force of the cord, T - mg = ma. So T = ma + mg For this I got 411.5 N To solve for work I multiplied it by 6.5m and got 2675.4J which is wrong. I am not sure what I am doing.

Homework Statement A cord is used to vertically lower an initially stationary block of mass M = 35 kg at a constant downward acceleration of g/5. When the block has fallen a distance d = 6.5 m, find the work done by the cord's force on the block. Find the work done by the weight of the block...

I did... Thank you so much!

Ok I think I got it

Homework Statement M1 and M2 are two masses connected as shown. https://loncapa2.physics.sc.edu/res/msu/physicslib/msuphysicslib/09_Force_and_Motion/graphics/prob75_fricpullplane.gif The pulley is light and frictionless. Find the mass M1, given that M2 (3.50 kg) is moving downwards and...

Yes it was a test question I got wrong so I was trying to find the correct method to the answer

I just call it a conversion

Right. so it would be 11.35 g/cm^3 * 1000000cm^3/1 m^3 to give 11350000 g/m^3 which you divide into 3.439*10^-22 g

But you're looking for m^3

100 so it would be cubed to get m^3 and it would be 3.03*10^-29 which is the right answer

Homework Statement Lead has a mass of 11.35 g per cubic centimeter of volume, and the mass of one of its atoms is 3.439×10-25 kg. If the atoms are spherical and tightly packed, what is the volume of an individual atom? ( m3) Homework Equations conversions The Attempt at a Solution For this...

Yes. Thank you for your help. Sorry for the late response I went to a research meeting.

Its the final velocity of the package so Vy

yes it takes 1.41s from V = Vi +at. V is now -13.86 m/s because the initial Velocity was 0 m/s