Recent content by KristinaMr

thank you for the exponent rule ..I somehow missed it yea it was a limit of x-> 1 so that the exponent would be 1/0 ..the exercise said to apply L Hopital rule to solve ( by the way the result should be e)

I encountered this problem is Hopital section...how do I even apply it?

thank you :thumbup:

the double bond breaks because bromines are detached from the ring leaving a place for hydrogens ...so now we are left with a saturated cyclohexane. Is it correct? ...and the two bromines just form Br2 (?)

I think that the double bond would be broken in some way but what happens to the two bromines? do they remain in the ring? (or does HBr forms? is it possible?)

Thank you for your help :)

α=(∆L/L)/T So the units are ℃^-1 because the temperature in the equation is in the denominator (which means T ^-1) . Right?

Homework Statement This is the problem. A pair of eyeglass frames is made of epoxy plastic. At room temperature (20.0°C), the frames have circular lens holes 2.20 cm in radius. To what temperature must the frames be heated if lenses 2.21 cm in radius are to be inserted in them? The average...

Thank you very much for your reply..Actually I have given up on this exercise, but then I returned to it and forced myself (successfully ) to find an answer. Have a good day :)

Hi welcome to PF !

I tried finding the components of a vector using at= a sin 30 and ar=a cos 30. ar is 12,9 m/s² and at = 7,5 m/s² . Then I found the velocity to be 5,67 m/s which looks to be approximately righ. But what if I have the two accelerations and need to find the angle between them?

Homework Statement A particle is moving clockwise in a circle of radius 2.50m at a given instant of time. I have to find radiant and tangential acceleration and the speed of the particle. The acceleration vector is 15.0 m/s² and the angle between the radius and the acceleration vector is 30°...

:-p