Recent content by Kristmas

Thank you Ehil, I got the answer to question 1 now. Worked out solution to question 2 as well. Change in heat is 0.2 x 2.26 x 106 Jkg-1=452 000 Joules Pressure is already given at 100 000 Pa Original volume is mass/density, so 0.2/1000=0.0002m3. Mass stays the same, so 0.2kg of steam occupies...

Sorry, I can't see it still. I know it has taken 710 000Joules of energy to get the ice to 0 Celisu and melt completely to water. So I thought i simply take that energy away from the water at 45 Celsius. Thus using Energy=mass*specific heat capacity of water* change in temperature to get the...

Hi there, I have some serious problems with a couple of questions. Need help for exam revision. 1.1 Homework Statement A 2kg chunck of ice at -10Celsius is added to 5kg of water at 45Celsius. What is the final temperature of the system? 1.2 Relevant equations specific heat capacity of ice -...