Recent content by kvan

If I use the height of the tank instead of the height of the stream I get ~1067MN. That number seems a little high. Please not that I don't actually have the answer. I was just told by my prof that my original method was wrong and recommended I use integration.

But how would that relate to the force of a liquid acting on a container that then breaks?

Homework Statement On the afternoon of January 15, 1919, an unusually warm day in Boston, a 28.1 m high, 27.4 m diameter cylindrical metal tank used for storing molasses ruptured. Molasses flooded the streets in a 9 meter deep stream, killing pedestrians and horses and knocking down...

Homework Statement A space craft, traveling at 0.77c, is just passing the Earth when the light from a Supernova which is traveling in exactly the opposite direction to the ship, reaches it. According to an observer on the Earth the star which caused the explosion was 720 light years away (1...

I got the answer finally, thanks so much for the help. :D

Oh man, I can't believe I messed that up. I tried using the method you put but I don't think it works, or I did something wrong. v_f_y = v_f_i - gt 0 = 650\sin\theta - 9.8t t = \frac{650\sin\theta}{9.8} T = 2t = 2* \frac{650\sin\theta}{9.8} T = \frac {650\sin\theta}{4.9}...

Thanks, well my component vectors look like this y= 650\sin\theta x= 650\cos\theta I use the y value and plugged it into v^2_y= v^2_0_y + 2gt rearranged into \frac {t = v^2_y - v^2_0_y}{2g} \frac {0^2 - (650\sin\theta)^2}{-9.8*2} since this value for t is just the time taken to...

Homework Statement An artillery gun is trying to hit a target that is 12.5 km away. If the shell is fired at 650 ms-1 at what angle above the horizontal should the gun be fired to hit the target assuming that air resistance is negligible? [g=9.8 ms-2] Homework Equations I tried using v^2_y...