Recent content by kyze

Thanks athuss. Great idea. I guess it could also work for a square duct with a bend also? But this all leads to a final geometry which is absolutely irregular, say the carotid blood artery that need to be unwrapped. So do you think applying polar coordinates would work?

Since v represents velocity, can I then integrate the v-equation? Are inv. Beta functions integratable? Or would it be simpler to determine the x-position by setting up the original equation as a second order derivative as: d2xdt2−A(B−v)^1.6=G and as B = 0 then...

Hi, I am not very strong in maths, so sorry if these sounds simple. If I have a 3D geometry of a pipe which has its surface defined by triangles (such as that in Computational Fluid Dynamics or Finite Element Analysis) and I have the coordinate points for all the triangles, how can I...

wow! thanks

Hi, Just realized I can make an assumption for B = 0. Does this make it solvable?

hi all, I've been trying to work this problem out, \frac{dv}{dt}-A(B-v)^{1.6}=G A, B and G are constants and Matlab can't give me a solution either. I'm wondering if there is even a solution?