Recent content by Laura08
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Why Does the Momentum Operator Yield Different Results in Rotations?
Well, I think the calculation is correct, but then I did a backwards rotation, which I didn't intend to do. The rotation matrix for an infinitesimal rotation about the z-axis is (if I rotate the vector, not the system) R_{z}(d\phi) = \left(\begin{array}{ccc} 1 & -d\phi & 0\\ d\phi & 1 &...- Laura08
- Post #5
- Forum: Advanced Physics Homework Help
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Why Does the Momentum Operator Yield Different Results in Rotations?
I just use the operator on each component: [1-\frac{i}{\hbar} d\phi (xp_{y}-yp_{x})] | x,y,z \rangle = [1-d\phi (x \frac{\partial}{\partial y}-y \frac{\partial}{\partial x})] | x,y,z \rangle = |x-d\phi (x \frac{\partial x}{\partial y}-y \frac{\partial x}{\partial x}),y-d\phi (x...- Laura08
- Post #3
- Forum: Advanced Physics Homework Help
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Why Does the Momentum Operator Yield Different Results in Rotations?
Hello, sorry I am new to this forum, I hope I found the right category. I have a question about the momentum operator as in Sakurai's "modern quantum mechanics" on p. 196 If I let 1-\frac{i}{\hbar} d\phi L_{z} = 1-\frac{i}{\hbar} d\phi (xp_{y}-yp_{x}) act on an eigenket | x,y,z...- Laura08
- Thread
- Angular Angular momentum Angular momentum operator Momentum Operator Orbital Orbital angular momentum
- Replies: 4
- Forum: Advanced Physics Homework Help