Recent content by Le_Anthony
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Studying Create the Perfect Self-Study Routine
Thanks for the input. I have one more question. I am considering learning the entire course in the off season( say like summer). But what I am afraid of is, what if i teach myself the concepts incorrectly?(If that's possible...) And the way i learned the concept is not the way my instructor...- Le_Anthony
- Post #3
- Forum: STEM Academic Advising
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Studying Create the Perfect Self-Study Routine
I've noticed that my routine for studying mathematics, physics, chemistry etc. isn't doing me any good. It seems that no matter how much effort i put into studying the material, I am always one step behind and my test scores come back horrible. My current routine will be to read through the...- Le_Anthony
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- Self Self study Study
- Replies: 5
- Forum: STEM Academic Advising
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Projectile is fired over level ground
Thanks!- Le_Anthony
- Post #5
- Forum: Introductory Physics Homework Help
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Projectile is fired over level ground
What do you mean?- Le_Anthony
- Post #3
- Forum: Introductory Physics Homework Help
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Projectile is fired over level ground
Homework Statement A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal component of 30 m/s. Using g = 10 m/s2, the distance from launching to landing points is: Homework Equations Vi(t) +0.5at^2 The Attempt at a Solution I...- Le_Anthony
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- Ground Projectile
- Replies: 4
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Thanks. Kinda sad to know now haha but at least I know- Le_Anthony
- Post #8
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
To cancel out gravity add 9.8 to 1.8 bc it needs to move upward. 425 kg(11.6ms2)(85 m)- Le_Anthony
- Post #6
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Is it 4.2x10^5 J- Le_Anthony
- Post #4
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Homework Statement Had a question on a test went something like this; A crane lifts a 425 kg bar 85m above the ground. The crane is lifting it upwards with an acceleration of 1.8 m/s^2. How much work is done by the crane? Homework Equations W=Fd The Attempt at a Solution Solution 1( the one i...- Le_Anthony
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- Crane Work Work done
- Replies: 12
- Forum: Introductory Physics Homework Help
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Calculating Work Done by a Spring
Homework Statement An ideal spring is hung vertically from the ceiling. When a 2.0 kg mass hangs from it at rest, the spring is extended 0.06 meters from its relaxed state. An upward external force is then applied to the block to move it upward a distance of 0.16 meters. While the block is...- Le_Anthony
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- Spring Work Work done
- Replies: 2
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
which i now realize i was thinking of W/Δt.. oops- Le_Anthony
- Post #6
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
So i just need to derive the equation and plug in 3.1s? I divided by 3.1 because instantaneous power is derivative of work w/ respect to time.- Le_Anthony
- Post #5
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
Homework Statement The energy of a system increases at a rate of 3.5t + 6.2t^2, in joules. What is the instantaneous power at t=3.1 s? Homework Equations P=dW/dt J/s=watt The Attempt at a Solution dW=3.5 + 12.4t P=(3.5 + 12.4t joule) / (3.1s)=1.12 + 4t, in watts Yes/ no?- Le_Anthony
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- Calculation Power Power calculation
- Replies: 5
- Forum: Introductory Physics Homework Help
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Calculating Power Requirements for an Escalator
Ahhhh i see. That saves a lot of time actually. I will do that on my test this friday. Thanks!- Le_Anthony
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Power Requirements for an Escalator
Homework Statement Homework Equations W=Fx*d P=W/Δt The Attempt at a Solution Shot in the dark but, 20 people with 60 kg mass=1200kg total mass. Weight=1200kg*9.8m/s^2=11760N. Force component along the incline is 11760N*sin(30)=5880N. Work=5880N* 10m=58800J.(The 10m was found from trig...- Le_Anthony
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- Power
- Replies: 2
- Forum: Introductory Physics Homework Help