Recent content by Le_Anthony
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Studying Why my study routine for STEM subjects isn't working
Thanks for the input. I have one more question. I am considering learning the entire course in the off season( say like summer). But what I am afraid of is, what if i teach myself the concepts incorrectly?(If that's possible...) And the way i learned the concept is not the way my instructor...- Le_Anthony
- Post #3
- Forum: STEM Academic Advising
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Studying Why my study routine for STEM subjects isn't working
I've noticed that my routine for studying mathematics, physics, chemistry etc. isn't doing me any good. It seems that no matter how much effort i put into studying the material, I am always one step behind and my test scores come back horrible. My current routine will be to read through the...- Le_Anthony
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- Self Self study Study
- Replies: 5
- Forum: STEM Academic Advising
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Projectile is fired over level ground
Thanks!- Le_Anthony
- Post #5
- Forum: Introductory Physics Homework Help
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Projectile is fired over level ground
What do you mean?- Le_Anthony
- Post #3
- Forum: Introductory Physics Homework Help
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Projectile is fired over level ground
Homework Statement A projectile is fired over level ground with an initial velocity that has a vertical component of 20 m/s and a horizontal component of 30 m/s. Using g = 10 m/s2, the distance from launching to landing points is: Homework Equations Vi(t) +0.5at^2 The Attempt at a Solution I...- Le_Anthony
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- Ground Projectile
- Replies: 4
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Thanks. Kinda sad to know now haha but at least I know- Le_Anthony
- Post #8
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
To cancel out gravity add 9.8 to 1.8 bc it needs to move upward. 425 kg(11.6ms2)(85 m)- Le_Anthony
- Post #6
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Is it 4.2x10^5 J- Le_Anthony
- Post #4
- Forum: Introductory Physics Homework Help
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Work Done by Crane: Calculating Force & Acceleration
Homework Statement Had a question on a test went something like this; A crane lifts a 425 kg bar 85m above the ground. The crane is lifting it upwards with an acceleration of 1.8 m/s^2. How much work is done by the crane? Homework Equations W=Fd The Attempt at a Solution Solution 1( the one i...- Le_Anthony
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- Crane Work Work done
- Replies: 12
- Forum: Introductory Physics Homework Help
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Calculating Work Done by a Spring
Homework Statement An ideal spring is hung vertically from the ceiling. When a 2.0 kg mass hangs from it at rest, the spring is extended 0.06 meters from its relaxed state. An upward external force is then applied to the block to move it upward a distance of 0.16 meters. While the block is...- Le_Anthony
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- Spring Work Work done
- Replies: 2
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
which i now realize i was thinking of W/Δt.. oops- Le_Anthony
- Post #6
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
So i just need to derive the equation and plug in 3.1s? I divided by 3.1 because instantaneous power is derivative of work w/ respect to time.- Le_Anthony
- Post #5
- Forum: Introductory Physics Homework Help
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Instantaneous Power calculation
Homework Statement The energy of a system increases at a rate of 3.5t + 6.2t^2, in joules. What is the instantaneous power at t=3.1 s? Homework Equations P=dW/dt J/s=watt The Attempt at a Solution dW=3.5 + 12.4t P=(3.5 + 12.4t joule) / (3.1s)=1.12 + 4t, in watts Yes/ no?- Le_Anthony
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- Calculation Power Power calculation
- Replies: 5
- Forum: Introductory Physics Homework Help
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Calculating Power Requirements for an Escalator
Ahhhh i see. That saves a lot of time actually. I will do that on my test this friday. Thanks!- Le_Anthony
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Power Requirements for an Escalator
Homework Statement Homework Equations W=Fx*d P=W/Δt The Attempt at a Solution Shot in the dark but, 20 people with 60 kg mass=1200kg total mass. Weight=1200kg*9.8m/s^2=11760N. Force component along the incline is 11760N*sin(30)=5880N. Work=5880N* 10m=58800J.(The 10m was found from trig...- Le_Anthony
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- Power
- Replies: 2
- Forum: Introductory Physics Homework Help