Sorry for the late response. I had classes all day and got caught up with other hw.
So I thought about what you said but instead of considering velocities I set up a simpler equation (after all this was an exam so there HAD to be easier way).
I considered displacement:
x(2)-x(1) = 13...
Homework Statement
An object starts from rest at time t=0.00 s and moves in the +x direction with constant acceleration. The object travels 13.0 m from time t=1.00s to time t=2.00 s. What is the acceleration of the object?
a) 5.20 m/s^2
b) 10.4 m/s^2
c) 8.67 m/s^2
d) 6.93 m/s^2
e) 12.1...
Homework Statement
Two iceboats hold a race on a frictionless horizontal lake. The two iceboats have masses m and 2m. Each iceboats has an identical sail, so the wind exerts the same constant force F on each boat. The two ice boats start from rest and cross the finish line a distance s away...
Think about Newton's second law: F=ma
What is the acceleration of m1? What is the acceleration of m2?
consider gravity and the coordinate system Mentz114 has chosen when drawing free body diagrams for both blocks. That should answer your question.
You were right. I was missing the work don't by the parallel component of gravity which was +mgsin(theta)d. Using this quantity for the equation gives : d= .775 which is answer 'b'.
Thank you Doc Al
Ok so if I consider the work done by gravity's horizontal component through the distance 'd' as -mgdcos(theta) and plug that value into the left side of my Work-Energy equation.
My new result is:
d = .1087006786 m or approximately .108 m.
My new result is off by a factor of 10 from the choice...
Homework Statement
A box is sliding down an incline tilted at a 11.1° angle above the horizontal. The box is initially sliding down the incline at a speed of 1.70 m/s. The coefficient of kinetic friction between the box and the incline is 0.390. How far does the box slide down the incline...