Recent content by Levilaon

Ok I see, but I don't see mass in your equation. I quote from your post: "v(Δt)≐50−Δt⋅50^2 v(2Δt)≐v(Δt)−Δt⋅v(Δt)^2 ..." I believe it should be modified like this, after all acceleration is force/mass. v(Δt)≐50−Δt⋅(50^2)/m v(2Δt)≐v(Δt)−Δt⋅(v(Δt)^2)/m ... Tell me if I am mistaken.

Ok with my calculations it comes again that time is infinite until velocity reach 0, what did you get? I solved it like this: v=f(t), v₁=50, v₂=10, m=10, Fr=f(t)² f(t)=v₁-a·∆t => f(t)=v₁- (f(t)²/m)·∆t => (∆t/m)⋅f(t)²+f(t)-v₁ = 0 So when velocity is f(t)=v₂ then...

Can you try calculate time it would take it to come to 0 velocity. If your technique is valid you should get error or infty. EDIT: ok I did something bad, it never comes to infinity it goes to limes.

I think you got something wrong.

I got that time it took object to slow from 50 to10 km/s is 4 s and distance it passed during that time is 62.76 m.

I solved it, first I wrote function v=f(t) then found ▲t by simply putting in final velocity. Then I integrated that function with domain ▲t to get distance.

Homework Statement If we have object with mass 10 kg traveling at starting velocity of 50 km/s and one force of resistance that is equal to v^2 of object's velocity how can we calculate distance and time in which that object travels until it gets to velocity of 10 km/s.Homework EquationsThe...