Homework Statement
This circuit shows a 10Kohm potentiomiter with a 5Kohm load.
determine the position of the slider on the 'pot' when the voltage acreoss points 'xx' is 3V
ok so the 10K resistor is a potentiometer which is a variable resistor, so what they are asking when they say...
OK so
Linear accereration = V/T
=0.33/1.5 = 0.22
Angular acceleration =
2 (D-VoT)/T(2) = A
A = 2(0.5-0)/1.5(2) = 0.44
Angular acceleration = 0.44
VF= final velocity
VF=Vi+AT
VF=0+0.44X1.5
VF=0.66
Moment of inertia =
=MXradius of gyration (2)
=0.5X0.212(2) = 0.022472...
Apologise in advance I'm not good at these
D=vot+0.5at2
=0.5=0x1.5+0.5xax1.5(2)
=0.5=0.5xax1.5(2)
=ax1.5(2)=0.5/0.5
=ax1.5(2)=1
=a=1/1.5(2)
=a=1/2.25
=a=0.44
Cheers
I see I guess I have to make a the subject?
•d = vo • t + 0.5 • a • t2
I'm not very good at this
D-1/2xaxt2=v1xt
1/2xaxt2=[v1xt2]+d
So
1/2a = (v1xt2)+d/t2
How does that look? Also by t2 are they referring to time again?
Cheers
•d = vo • t + 0.5 • a • t2
•vf = vo + a • t
•vf2 = vo 2 + 2 • a • d
•d = (vo + vf)/ 2 • t
where
•d = displacement
•t = time
•a = acceleration
•vo = original or initial velocity
•vf = final velocity
these are the only kinematic equations i could find. seems hard to find the final...
I see that makes sense. I am struggling to figure out maximum velocity.
How about this
VMAX
Potential energy of mass = MGH
=0.5X9.81X0.5
= 2.45 J
Kinetic energy at bottom = potential energy at top...
could the tension in the rope simply be mass X acceleration = 5 X 0.219 = 1.095
or does gravity have to play a part?
would this make more sense?
tension = mass X (gravity X acceleration)
= 5 X(9.81 X 0.219) = 10.74 ?
Ok so this is were I am so far after taking your advise
Linear acceleration = mass max velocity – initial velocity/ time
= 0.33-0/1.5 = 0.22 ms -2
Angular acceleration = max wheel speed – initial wheel speed / time
Max wheel speed = velocity / radius = 0.33/0.3 = 1.1 rad s -1...
how to work out "frictional torque" and "resisting motion"
Hi there,
if I have a scenario were a Mass is suspended from a flywheel. If the mass is released from rest and falls a distance in an amount of time.
how would i work out the
frictional torque
and resisting motion
does...
how to work out "frictional torque"
A Mass of 0.5 kg is suspended from a flywheel. If the mass is released from rest and falls a distance of 0.5 m in 1.5 s, calculate
the tension on the rope
the frictional torque, resisting motion
Mass of flywheel = 3 kg
radius of wheel = 300mm
radius...
also i have tryed working out:
velocity = distance/ time = 5/0.92 = 5.43 ms -1
acceleration = change of velocity / time taken = 0 - 5.43 (final velocity) / 0.92 which is 5.902 m s -2
Homework Statement
this is the scenario
A horizontal force of 80N acts on a mass of 6 Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and...