Need guidance finding the total energy expanded in acceleration

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SUMMARY

The total energy expanded in the acceleration of a 6 kg mass subjected to an 80 N horizontal force over a distance of 5 m is calculated using the work-energy principle. The work done, which equals the total energy expanded, is determined to be 400 joules, derived from the formula Work = Force x Distance. The acceleration of the mass is calculated to be 5.902 m/s², confirming that the force applied results in the expected motion without energy losses.

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  • Understanding of Newton's Second Law of Motion
  • Familiarity with the work-energy principle
  • Basic knowledge of kinematics
  • Ability to perform calculations involving force, mass, and acceleration
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  • Learn about kinematic equations for uniformly accelerated motion
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Homework Statement



this is the scenario

A horizontal force of 80N acts on a mass of 6 Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant

Calculate the total energy expanded in the acceleration

Homework Equations





The Attempt at a Solution



By total energy expanded do I need the:

Work done = force X distance = 80 X 5 = 400 joules

Or have I got to find something else?

Thanks
 
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also i have tryed working out:

velocity = distance/ time = 5/0.92 = 5.43 ms -1

acceleration = change of velocity / time taken = 0 - 5.43 (final velocity) / 0.92 which is 5.902 m s -2
 

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