Yes. That's why I'm so confused.
I enter 1.11 x 10^3 for the first part and it reads back correct, so 1110 is the max height.
Let me double check the y velocity.
sin(57.5) = Vy/V0
sin(57.5) = Vy/175.0
175.0*sin(57.5) = Vy
147.6 = Vy
Why do I keep doing this? I need to double check...
Homework Statement
A projectile is fired at 57.5 deg above the horizontal. Its initial speed is equal to 175.0 m/s. Assume that the free-fall acceleration is constant throughout and that the effects of the air can be ignored. What is the maximum height reached by the projectile? At what...
Okay, that did get the ball rolling. I figured it was 45.0 degrees, so I calculated Vx and Vy.
Vx = 7.78 m/s
Vy = 7.78 m/s
Then I plugged in these values to this equation to find t:
X(t) = X0 + Vx0t
90 = 0 + 7.78t
11.6 s = t
So then I plug t = 11.6 s into this equation:
Y(t) = Y0 + Vy0t -...
Homework Statement
An astronaut kicks a football on a level area of planet Zog. He kicks the ball repeatedly at a wide range of angles from nearly zero to almost 90 deg above the horizontal, but always as hard as he can which gives an initial velocity of 11.7 m/s. The astronaut notices that...
No, trust me. I'd much rather understand the concepts. All of this stuff is built on, so if I don't get the concepts now, I will feel the pain later in the semester.
Your explanation was very helpful! Thank you so much.
Thank you for bearing with me.
- The average velocity from A to B will be negative because V = change in displacement / change in time and the change in displacement will be negative.
- Then, for the displacement from D to E, it should be less than zero because the final is less than the...
- Displacement will always be less than or equal to distance traveled because displacement is just the shortest distance between an initial point and the resting point. So, if you take an exact straight line, distance traveled will be equal to displacement. But, you can also take any other...
I think what I have is wrong is the instantaneous acceleration. At C, if the velocity starts to go down, then it must be decelerating... which means instantaneous acceleration would be less than 0.