Recent content by Lilian Sa
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Star collapse in general relativity — pressure as a function of star radius
What I've done is using the TOV equations and I what I found at the end is: ##e^{[\frac{-8}{3}\pi G\rho]r^2+[\frac{16}{9}(G\pi\rho)^{2}]r^4}-\rho=P(r)## so I am sure that this is not right, if someone can help me knowing it I really apricate it :)- Lilian Sa
- Thread
- Collapse Einstein field equation Function General General relaivity General relativity Pressure Radius Relativity Star Star collapse
- Replies: 1
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
But it was given in the question that ##a## depends on ## t ## , I don't know if its legal to suppose that it does not depend on ## t ##. :(- Lilian Sa
- Post #12
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
I don't think so, because we have to get a diagonalized metric with the four coordinates, which include Y or the transformed Y.- Lilian Sa
- Post #10
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
I'll try rhis today, hope it will work. thanks very much!- Lilian Sa
- Post #7
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
but this additional cross term we have to equate it to zero and then we get the expression equal to zero, but that doesn't help :( or I am wrong?- Lilian Sa
- Post #6
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
This is what I got at the end: ## ds^2=-dt^2(1-\partial_tF)+d\tilde{x}^2+(\partial_yF+2a^2\partial_yF)dy^2+dz^2+d\tilde{x}dy(sa^2+2\partial_yF)+dtdy(2a^2\partial_tF+2\partial_tF\partial_yF)+d\tilde{x}dt(2\partial_tF) ## that means that I got ##F ## does not depend on any coordinate! but this is...- Lilian Sa
- Post #3
- Forum: Advanced Physics Homework Help
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Diagonalizing a metric by a coordinate transformation
I posted a thread yesterday and I think that I did not formulated it properly. So I have a metric ##{ds}^{2}=-{dt}^{2}+{dx}^{2}+2{a}^2(t)dxdy+{dz}^{2}## I was asked to find the the coordinate transformation so that I can get a diagonalized metric. so what I've done is I assumed a coordinate...- Lilian Sa
- Thread
- Coordinate Coordinate transformation Metric Transformation
- Replies: 12
- Forum: Advanced Physics Homework Help
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Graduate Looking for sources of information on Black Holes
Thank you all, I saved all of them :) -
Diagonalizing a metric by a coordinate transformation
hey there :) So I had a homework, and I was asked to diagonalize the metric ##{ds}^2=-{dt}^2+{dx}^2+2a^2(t)dxdy+{dz}^2## and to find the coordinate transformation for the coordinates of the new metric. so I found the coordinate transformation but the lecturer said that what I found is a...- Lilian Sa
- Thread
- Coordinate Coordinate transformation Metric Transformation
- Replies: 1
- Forum: Advanced Physics Homework Help
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First order differential equation involving a square root
yes rho depends on time- Lilian Sa
- Post #14
- Forum: Calculus and Beyond Homework Help
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First order differential equation involving a square root
Ok I am on it now, but why we have in the answer (t_*-t)^(2\3)- Lilian Sa
- Post #12
- Forum: Calculus and Beyond Homework Help
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First order differential equation involving a square root
replace r in R.- Lilian Sa
- Post #10
- Forum: Calculus and Beyond Homework Help
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First order differential equation involving a square root
Mentor note: Fixed the LaTeX It is a collapse of a non relativistic star under its own gravity. ##M(R)=4\pi \int\rho(t)r^2dr##- Lilian Sa
- Post #8
- Forum: Calculus and Beyond Homework Help
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First order differential equation involving a square root
let me be honest, both. I just did not understand it. In the numerator there is M as a function of R, and in the denominator there is the function R.- Lilian Sa
- Post #4
- Forum: Calculus and Beyond Homework Help