Recent content by lilphy

Hello; I'm struggling with pointwise and uniform convergence, I think that examples are going to help me understand Homework Statement Consider the Fourier sine series of each of the following functions. In this exercise de not compute the coefficients but use the general convergence theorems...

So I just use what I found in a/ ! Thank you for the answer !

If we add the effect of the mass of the rod, for the torque Is it just going to be -(M+m)g(l+√3L/2) sinθ ?

thank you for your help :smile:

For the torque tou told me that I forgot something. The force is applied at the center of the cube so it would be -mg(l+sqrt(3)L/2) sin(theta) ?

Add Md² to the moment of inertia where d is the distance between the com and the pivot, that is √3L/2+l ?

Oh I thought it was about the corner, i don't know why .. But the moI that I found is about a diagonal, and the rod is aligned with the diagonal, isn't it the same then ? if not, i don't think i understand your explanations... I took the origin about the com The moment of inertia Ixx Iyy Izz...

Using cosine direction, and the angle between the axis passing through a corner-com and an edge is 55° So for c/ he torque is just -mgl sin(φ) ? But what if the rod has a mass ?

Hello I am studying for my exam and found an interesting exercise that I'm trying to solve 1. Homework Statement A pendulum consists of a thin rod of length ℓ and mass m suspended from a pivot ∇ in the figure to the right. The bob is a cube of side L and mass M, attached to the rod so that the...

Oh yes of course, i think now i get it. Because the center of mass is in the 3-axis there is no contribution of it on I33 ! Thanks for your time and explanations

Oh right we will only have the contribution of the sphere, the inertia about the center of mass of the system is 2/5MR^2+Md2 with d the distance to the center of mass that is = Ra/(1+a)

The inertia is mR^2 with R the distance to the rotation axis, so it would be 0 ?

There is something I don't understand. When we calculate the total tensor of the moment of inertia, the Itot_33of the system point mass-sohere is equal to Isphere_33 in the center of mass. I don't understand why ?

So there is no component in e1 and e2, all the values not in the diagonal are 0 And I will get I11= I22= aM r2 and I33=0 ?

Homework Statement hello, i want to calculate the inertia tensor of the combination of a point mass and a sphere in the object's frame, the center of mass is at the origin. The point mass remains at the surface of the phere The sphere is uniform, radius r and mass M, and the point mass has mass...